9y^2-16x^2-64x-54y-127=0

解答

9 y^{2} - 16 x^{2} - 64 x - 54 y - 127 = 0

(h, k) = (- 2, 3), a = 4, b = 3

求解步骤

9 y^{2} - 16 x^{2} - 64 x - 54 y - 127 = 0

将

9 y^{2} - 16 x^{2} - 64 x - 54 y - 127 = 0

改写为标准双曲线方程形式

\frac{( y - 3 ) ^{2}}{4 ^{2}} - \frac{( x - ( - 2 ) ) ^{2}}{3 ^{2}} = 1

因此双曲线的性质为:

(h, k) = (- 2, 3), a = 4, b = 3

y^{2} = x^{2} + 2 x - 15

x^{2} - y^{2} - 2 = 0

9 y^{2} - 4 x^{2} - 36 = 0

6 (x + \frac{1}{3})^{2} - 6 (y - \frac{1}{2})^{2} + 24 = 0

(y)^{2} + (5)^{2} = (6 + 2 + x)^{2}