y>-4x^2-12x-8

Lösung

y > - 4 x^{2} - 12 x - 8

(h, k) = (- \frac{3}{2}, 1), p = - \frac{1}{16}

Schritte zur Lösung

y > - 4 x^{2} - 12 x - 8

Rewrite

y > - 4 x^{2} - 12 x - 8

in the standard form

4 (- \frac{1}{16}) (y - 1) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, 1), p = - \frac{1}{16}

x + y^{2} - 3 = 0

x^{2} - 10 x - 2 y + 19 = 0

y^{2} - 8 x - 6 y + 25 = 0

y 2 y - 18 x = - 26

(x + 2)^{2} = y + 1