4x^2-3y^2+3x+2y-3=0

解

4 x^{2} - 3 y^{2} + 3 x + 2 y - 3 = 0

(h, k) = (- \frac{3}{8}, \frac{1}{3}), a = \frac{155}{8 3}, b = \frac{155}{12}

解答ステップ

4 x^{2} - 3 y^{2} + 3 x + 2 y - 3 = 0

4 x^{2} - 3 y^{2} + 3 x + 2 y - 3 = 0

を標準的な双曲線のequationで書き換える

\frac{( x - ( - \frac{3}{8} ) ) ^{2}}{( \frac{155}{8 3} ) ^{2}} - \frac{( y - \frac{1}{3} ) ^{2}}{( \frac{155}{12} ) ^{2}} = 1

ゆえに双曲線の特性は:

(h, k) = (- \frac{3}{8}, \frac{1}{3}), a = \frac{155}{8 3}, b = \frac{155}{12}