What is the foci ((y+2)^2)/(36)-x^2=1 ?

The foci ((y+2)^2)/(36)-x^2=1 is (0,-2+sqrt(37)),(0,-2-sqrt(37))

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foci ((y+2)^2)/(36)-x^2=1

foci

\frac{( y + 2 ) ^{2}}{36} - x^{2} = 1

(0, - 2 + 37), (0, - 2 - 37)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{( y + 2 ) ^{2}}{36} - x^{2} = 1 :

Up-down Hyperbola with

(h, k) = (0, - 2), a = 6, b = 1

(0, - 2 + c), (0, - 2 - c)

Compute

c :

c = 6^{2} + 1^{2} : 37

(0, - 2 + 37), (0, - 2 - 37)

\frac{x ^{2}}{23} - \frac{y ^{2}}{2} = 1

9 x^{2} - 16 y^{2} - 18 x + 64 y - 199 = 0

49 y^{2} - 100 x^{2} = 4900

\frac{x ^{2}}{64} - \frac{y ^{2}}{4} = 1

\frac{( x - 1 ) ^{2}}{25} - \frac{( y - 2 ) ^{2}}{16} = 1

What is the foci ((y+2)^2)/(36)-x^2=1 ?
The foci ((y+2)^2)/(36)-x^2=1 is (0,-2+sqrt(37)),(0,-2-sqrt(37))