asymptoten 5y^2-16x^2+400=0

Lösung

asymptoten

5 y^{2} - 16 x^{2} + 400 = 0

y = \frac{4 x}{5}, y = - \frac{4 x}{5}

Schritte zur Lösung

y = \pm \frac{b}{a} (x - h) + k

Calculate Hyperbola properties

5 y^{2} - 16 x^{2} + 400 = 0 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 5, b = 45

y = \frac{4 5}{5} (x - 0) + 0, y = - \frac{4 5}{5} (x - 0) + 0

Fasse zusammen

y = \frac{4 x}{5}, y = - \frac{4 x}{5}

a sy m pt o t es - 25 x^{2} + y^{2} = 25

a sy m pt o t es 5 x^{2} - 6 y^{2} - 20 x + 12 y - 16 = 0

a sy m pt o t es \frac{y ^{2}}{1 2 ^{2}} - \frac{x ^{2}}{6 ^{2}} = 1

a sy m pt o t es x^{2} - 4 (y - 3)^{2} = 4

a sy m pt o t es 16 y^{2} - 81 x^{2} - 256 y + 486 x = 1001