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Beliebt Geometry >

center 4y^2-49x^2-392x+16y-964=0

Lösung

center

4 y^{2} - 49 x^{2} - 392 x + 16 y - 964 = 0

Lösung

(- 4, - 2)

Schritte zur Lösung

4 y^{2} - 49 x^{2} - 392 x + 16 y - 964 = 0

Rewrite

4 y^{2} - 49 x^{2} - 392 x + 16 y - 964 = 0

in the form of a standard hyperbola equation

\frac{( y - ( - 2 ) ) ^{2}}{7 ^{2}} - \frac{( x - ( - 4 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 4, - 2), a = 7, b = 2

And the center is:

(- 4, - 2)

Graph

Beliebte Beispiele

center (y^2)/9-(x^2)/(16)=1

ce n t er \frac{y ^{2}}{9} - \frac{x ^{2}}{16} = 1

center x^2-y^2=16

ce n t er x^{2} - y^{2} = 16

center (x^2)/4-(y^2)/9 =1

ce n t er \frac{x ^{2}}{4} - \frac{y ^{2}}{9} = 1

center (x^2)/(144)-(y^2)/(25)=1

ce n t er \frac{x ^{2}}{144} - \frac{y ^{2}}{25} = 1

center ((x-5)^2)/(36)-(y^2)/(64)=1

ce n t er \frac{( x - 5 ) ^{2}}{36} - \frac{y ^{2}}{64} = 1