center x^2-16y^2=144

Lösung

center

x^{2} - 16 y^{2} = 144

(0, 0)

Schritte zur Lösung

x^{2} - 16 y^{2} = 144

Rewrite

x^{2} - 16 y^{2} = 144

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{1 2 ^{2}} - \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 12, b = 3

And the center is:

(0, 0)

ce n t er \frac{( y - \frac{1}{2} ) ^{2}}{2} - \frac{( x + 2 ) ^{2}}{4} = 1

ce n t er - 9 x^{2} + y^{2} - 72 x - 153 = 0

ce n t er \frac{( x - 3 ) ^{2}}{8 ^{2}} - \frac{( y - 2 ) ^{2}}{8 ^{2}} = 1

ce n t er \frac{( x + 2 ) ^{2}}{36} - \frac{( y - 3 ) ^{2}}{16} = 1

ce n t er x^{2} - y^{2} - 6 x = 7