What is the eccentricity 0=-400/9 x^2+16y^2+400 ?

The eccentricity 0=-400/9 x^2+16y^2+400 is (sqrt(34))/3

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eccentricity 0=-400/9 x^2+16y^2+400

eccentricity

0 = - \frac{400}{9} x^{2} + 16 y^{2} + 400

\frac{34}{3}

Solution steps

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

0 = - \frac{400}{9} x^{2} + 16 y^{2} + 400 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 5

= \frac{3 ^{2} + 5 ^{2}}{3}

Refine

= \frac{34}{3}

\frac{x ^{2}}{121} - \frac{y ^{2}}{81} = 1

\frac{x ^{2}}{27} - \frac{y ^{2}}{216} = 1

x^{2} - \frac{y ^{2}}{4} = 1

9 x^{2} - 25 y^{2} = 225

\frac{x ^{2}}{60} - \frac{y ^{2}}{40} = 1

What is the eccentricity 0=-400/9 x^2+16y^2+400 ?
The eccentricity 0=-400/9 x^2+16y^2+400 is (sqrt(34))/3