y-4x^2=0

Lösung

y - 4 x^{2} = 0

(h, k) = (0, 0), p = \frac{1}{16}

Schritte zur Lösung

y - 4 x^{2} = 0

Rewrite

y - 4 x^{2} = 0

in the standard form:

4 \cdot \frac{1}{16} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{16}

(x + 1)^{2} = - 12 (y - 6)

x^{2} + (y - 3) 2 = 16

x + (y - 1)^{2} = 1

x - 2 y^{2} - 12 y - 13 = 0

2 x^{2} - 2 y = 0