q^2=g(-h+a)

Lösung

q^{2} = g (- h + a)

(h, k) = (0, a), p = - \frac{g}{4}

Schritte zur Lösung

q^{2} = g (- h + a)

Rewrite

q^{2} = g (- h + a)

in the standard form:

4 (- \frac{g}{4}) (h - a) = (q - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, a), p = - \frac{g}{4}

f (x) (a + b) = x^{2}

(x - 5)^{2} = 24 (y - 3)

4 y^{2} + 16 y - 6 x - 2 = 0

y^{2} - 6 y + 9 = 12 x - 24

y^{2} - x + 4 y + 6 = 0