x^2-2x+6y+13=0

Lösung

x^{2} - 2 x + 6 y + 13 = 0

(h, k) = (1, - 2), p = - \frac{3}{2}

Schritte zur Lösung

x^{2} - 2 x + 6 y + 13 = 0

Rewrite

x^{2} - 2 x + 6 y + 13 = 0

in the standard form

4 (- \frac{3}{2}) (y - (- 2)) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, - 2), p = - \frac{3}{2}

y^{2} = - 40 x

y > - x^{2} - 4 x - 7

(y + 3)^{2} = 12 (x + 1)

x = - y^{2} + 5

\frac{1}{y} - \frac{1}{x ^{2}} = 0