x+y^2-3>= 0

Lösung

x + y^{2} - 3 \geq 0

(h, k) = (3, 0), p = - \frac{1}{4}

Schritte zur Lösung

x + y^{2} - 3 \geq 0

Rewrite

x + y^{2} - 3 \geq 0

in the standard form:

4 (- \frac{1}{4}) (x - 3) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (3, 0), p = - \frac{1}{4}

x \frac{x}{5} = \frac{y}{4}

y^{2} = 4 x + 9

4 x + y^{2} = 32

2 x^{2} + y \geq 0

y^{2} - 5 x = 0