2x^2+8y-12=0

Lösung

2 x^{2} + 8 y - 12 = 0

(h, k) = (0, \frac{3}{2}), p = - 1

Schritte zur Lösung

2 x^{2} + 8 y - 12 = 0

Rewrite

2 x^{2} + 8 y - 12 = 0

in the standard form:

4 (- 1) (y - \frac{3}{2}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{3}{2}), p = - 1

- 5 x^{2} + 7 y - 11 = 0

x (2 x - 5) = z

x^{2} + 12 y + 12 = 0

x = 27 y - 5 y^{2}

2 x^{2} + 9 x - k (x) = 0