-y^2=8x+12y

Lösung

- y^{2} = 8 x + 12 y

(h, k) = (\frac{9}{2}, - 6), p = - 2

Schritte zur Lösung

- y^{2} = 8 x + 12 y

Rewrite

- y^{2} = 8 x + 12 y

in the standard form

4 (- 2) (x - \frac{9}{2}) = (y - (- 6))^{2}

Therefore parabola properties are:

(h, k) = (\frac{9}{2}, - 6), p = - 2

y^{2} + 4 y = x

1 - x^{2} - y \geq 0

yy - (- 4) = 0.4 (x - (- 2))

x^{2} + 2 m (x) + 10 = 0

5 a + 5 \frac{b}{a} = - 5