3x^2-2y+1=0

Lösung

3 x^{2} - 2 y + 1 = 0

(h, k) = (0, \frac{1}{2}), p = \frac{1}{6}

Schritte zur Lösung

3 x^{2} - 2 y + 1 = 0

Rewrite

3 x^{2} - 2 y + 1 = 0

in the standard form:

4 \cdot \frac{1}{6} (y - \frac{1}{2}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{1}{2}), p = \frac{1}{6}

49 f (x) = (x - 10)^{2} - 49

x^{2} - 4 x = 2 y

(y + 2)^{2} = 16 (x - 2)

x = - 3 (y + 5)^{2} - 6

y^{2} = 6 x - 10