(x^2)/(16)+(y^2)/(49)=1

Lösung

\frac{x ^{2}}{16} + \frac{y ^{2}}{49} = 1

(h, k) = (0, 0), a = 4, b = 7

Schritte zur Lösung

\frac{x ^{2}}{16} + \frac{y ^{2}}{49} = 1

Rewrite

\frac{x ^{2}}{16} + \frac{y ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 7, a = 4

v er t i ces \frac{x ^{2}}{25} + \frac{y ^{2}}{25} = 1

a sy m pt o t es \frac{y ^{2}}{64} - \frac{x ^{2}}{36} = 1

\frac{( x - 1 ) ^{2}}{25} - \frac{( y + 3 ) ^{2}}{9} = 1

v er t i ces f (x) = x^{2} - 2 x + 4

v er t i ces x^{2} - 24 x - 12