-x^2+2x-4y=6

Lösung

- x^{2} + 2 x - 4 y = 6

(h, k) = (1, - \frac{5}{4}), p = - 1

Schritte zur Lösung

- x^{2} + 2 x - 4 y = 6

Rewrite

- x^{2} + 2 x - 4 y = 6

in the standard form

4 (- 1) (y - (- \frac{5}{4})) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, - \frac{5}{4}), p = - 1

y + 4 = x^{2}

x + y = y^{2} - 3

9 x^{2} - 16 y = 144

- 20 x + y^{2} - 6 y + 49 = 0

x^{2} - 32 y = 0