x^2-40y=-200

Lösung

x^{2} - 40 y = - 200

(h, k) = (0, 5), p = 10

Schritte zur Lösung

x^{2} - 40 y = - 200

Rewrite

x^{2} - 40 y = - 200

in the standard form:

4 \cdot 10 (y - 5) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 5), p = 10

- y^{2} - 2 x = 4

3 y + x^{2} = 0

- 4.9 x^{2} + 16.8 x_{+} 7.6 = 0

y (n) = n x^{2} (n)

- f (x) = 3 x - x^{2}