y>x^2+2x-5

Lösung

y > x^{2} + 2 x - 5

(h, k) = (- 1, - 6), p = \frac{1}{4}

Schritte zur Lösung

y > x^{2} + 2 x - 5

Rewrite

y > x^{2} + 2 x - 5

in the standard form

4 \cdot \frac{1}{4} (y - (- 6)) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 6), p = \frac{1}{4}

y^{2} = - 4 p (x - h)

x^{2} + 3 x + y = - 4

x 3 x + 5 y = 10

x = 2 y^{2} - 20 y + 52

3 x^{2} + 10 = 17 z