2x^2-y-1=0

Lösung

2 x^{2} - y - 1 = 0

(h, k) = (0, - 1), p = \frac{1}{8}

Schritte zur Lösung

2 x^{2} - y - 1 = 0

Rewrite

2 x^{2} - y - 1 = 0

in the standard form:

4 \cdot \frac{1}{8} (y - (- 1)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 1), p = \frac{1}{8}

x^{2} + 2 s - 6 = 0

(x + 5)^{2} = 7 (y + 2)

x^{2} + 2 y = 5

x^{2} + 2 y = 6

\frac{y - 7.09}{0.01} = x^{2} + 25 x