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Beliebt Geometry >

leitkurve y^2+28x=0

Lösung

leitkurve

y^{2} + 28 x = 0

Lösung

x = 7

Schritte zur Lösung

Rewrite

y^{2} + 28 x = 0

in the standard form:

4 (- 7) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - 7

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- 7)

Fasse zusammen

x = 7

Graph

Beliebte Beispiele

leitkurve y=4x^2-24x+31

d i rec t r i x y = 4 x^{2} - 24 x + 31

leitkurve y=-x^2+4x

d i rec t r i x y = - x^{2} + 4 x

leitkurve y^2+4x-14y=-53

d i rec t r i x y^{2} + 4 x - 14 y = - 53

leitkurve y=6x^2+12x

d i rec t r i x y = 6 x^{2} + 12 x

leitkurve y=-4(x-2)^2+16

d i rec t r i x y = - 4 (x - 2)^{2} + 16