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Beliebt Geometry >

leitkurve y=16x^2+1

Lösung

leitkurve

y = 16 x^{2} + 1

Lösung

y = \frac{63}{64}

Schritte zur Lösung

Rewrite

y = 16 x^{2} + 1

in the standard form:

4 \cdot \frac{1}{64} (y - 1) = (x - 0)^{2}

(h, k) = (0, 1), p = \frac{1}{64}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 1)

y-coordinate

y = 1 - p

y = 1 - \frac{1}{64}

Fasse zusammen

y = \frac{63}{64}

Graph

Beliebte Beispiele

leitkurve y=(6x)/7 (4x)/3

d i rec t r i x y = \frac{6 x}{7} \frac{4 x}{3}

leitkurve-1/3 (x-3)=(y+5)^2

d i rec t r i x - \frac{1}{3} (x - 3) = (y + 5)^{2}

leitkurve+2.5t^2+6t

d i rec t r i x + 2.5 t^{2} + 6 t

leitkurve y=x^2+6x+8

d i rec t r i x y = x^{2} + 6 x + 8

leitkurve-5t^2+20t

d i rec t r i x - 5 t^{2} + 20 t