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Beliebt Geometry >

leitkurve 4y^2+3x=0

Lösung

leitkurve

4 y^{2} + 3 x = 0

Lösung

x = \frac{3}{16}

Schritte zur Lösung

Rewrite

4 y^{2} + 3 x = 0

in the standard form:

4 (- \frac{3}{16}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{3}{16}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- \frac{3}{16})

Fasse zusammen

x = \frac{3}{16}

Graph

Beliebte Beispiele

leitkurve (x-1)^2=y-2

d i rec t r i x (x - 1)^{2} = y - 2

leitkurve x^2-4x+2

d i rec t r i x x^{2} - 4 x + 2

leitkurve x^2-4x+3

d i rec t r i x x^{2} - 4 x + 3

leitkurve y=3x-3x^2

d i rec t r i x y = 3 x - 3 x^{2}

leitkurve x^2-4x+1

d i rec t r i x x^{2} - 4 x + 1