leitkurve y=x^2-5x3

Lösung

leitkurve

y = x^{2} - 5 x 3

y = - \frac{113}{2}

Schritte zur Lösung

Rewrite

y = x^{2} - 5 x \cdot 3

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{225}{4})) = (x - \frac{15}{2})^{2}

(h, k) = (\frac{15}{2}, - \frac{225}{4}), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{15}{2}, - \frac{225}{4})

y-coordinate

y = - \frac{225}{4} - p

y = - \frac{225}{4} - \frac{1}{4}

Fasse zusammen

y = - \frac{113}{2}

d i rec t r i x y = (x - \frac{24}{x + 2}) (x - \frac{12}{x - 4})

d i rec t r i x x = (y + 1) y

d i rec t r i x (x - 9)^{2} - 6

d i rec t r i x x^{2} - 16 y = 0

d i rec t r i x 0.8 x^{2} + 500 x - 25000