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Beliebt Geometry >

leitkurve y=x^2+7x+5

Lösung

leitkurve

y = x^{2} + 7 x + 5

Lösung

y = - \frac{15}{2}

Schritte zur Lösung

Rewrite

y = x^{2} + 7 x + 5

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{29}{4})) = (x - (- \frac{7}{2}))^{2}

(h, k) = (- \frac{7}{2}, - \frac{29}{4}), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- \frac{7}{2}, - \frac{29}{4})

y-coordinate

y = - \frac{29}{4} - p

y = - \frac{29}{4} - \frac{1}{4}

Fasse zusammen

y = - \frac{15}{2}

Graph

Beliebte Beispiele

leitkurve y=-10x^2

d i rec t r i x y = - 10 x^{2}

leitkurve y=-2x^2-3

d i rec t r i x y = - 2 x^{2} - 3

leitkurve x^2-2x-4y+17=0

d i rec t r i x x^{2} - 2 x - 4 y + 17 = 0

leitkurve x^2-12y-6x+5=0

d i rec t r i x x^{2} - 12 y - 6 x + 5 = 0

leitkurve x^2+4x-y+1=0

d i rec t r i x x^{2} + 4 x - y + 1 = 0