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受欢迎的初等代数 >

(1+1/8)× (2-16/9)

解答

(1 + \frac{1}{8}) \cdot (2 - \frac{16}{9})

解答

\frac{1}{4}

+1

十进制

0.25

求解步骤

(1 + \frac{1}{8}) (2 - \frac{16}{9})

遵循 PEMDAS 运算顺序

计算括号内的值

(1 + \frac{1}{8}) : \frac{9}{8}

1 + \frac{1}{8}

1 + \frac{1}{8} = \frac{9}{8}

1 + \frac{1}{8}

将项转换为分式:

1 = \frac{1 \cdot 8}{8}

= \frac{1 \cdot 8}{8} + \frac{1}{8}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 8 + 1}{8}

1 \cdot 8 + 1 = 9

1 \cdot 8 + 1

数字相乘:

1 \cdot 8 = 8

= 8 + 1

数字相加:

8 + 1 = 9

= 9

= \frac{9}{8}

= \frac{9}{8}

= \frac{9}{8} (2 - \frac{16}{9})

计算括号内的值

(2 - \frac{16}{9}) : \frac{2}{9}

2 - \frac{16}{9}

2 - \frac{16}{9} = \frac{2}{9}

2 - \frac{16}{9}

将项转换为分式:

2 = \frac{2 \cdot 9}{9}

= \frac{2 \cdot 9}{9} - \frac{16}{9}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 9 - 16}{9}

2 \cdot 9 - 16 = 2

2 \cdot 9 - 16

数字相乘:

2 \cdot 9 = 18

= 18 - 16

数字相减:

18 - 16 = 2

= 2

= \frac{2}{9}

= \frac{2}{9}

= \frac{9}{8} \cdot \frac{2}{9}

乘除（左右）

\frac{9}{8} \cdot \frac{2}{9} : \frac{1}{4}

\frac{9}{8} \cdot \frac{2}{9}

交叉约去公约数:

9

= \frac{2}{8}

对数字约分

\frac{2}{8} = \frac{1}{4}

= \frac{1}{4}

= \frac{1}{4}

流行的例子

(33× 34)+(32\div 8)

(33 \times 34) + (32 \div 8)

-5(-3)+(7\div 3)

- 5 (- 3) + (7 \div 3)

(21 - 1) \times (- 20)

4^{5} - 5^{4}

\frac{17}{18} \cdot 3 + 1