What is -1\div 2-1\div 2 ?

The solution to -1\div 2-1\div 2 is -1

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-1\div 2-1\div 2

- 1 \div 2 - 1 \div 2

- 1

Solution steps

- 1 \div 2 - 1 \div 2

Follow the PEMDAS order of operations

Multiply and divide (left to right)

- 1 \div 2 : \frac{- 1}{2}

- 1 \div 2

- 1 \div 2 = \frac{- 1}{2}

= \frac{- 1}{2}

= \frac{- 1}{2} - 1 \div 2

Multiply and divide (left to right)

1 \div 2 : \frac{1}{2}

1 \div 2

1 \div 2 = \frac{1}{2}

= \frac{1}{2}

= \frac{- 1}{2} - \frac{1}{2}

Add and subtract (left to right)

\frac{- 1}{2} - \frac{1}{2} : - 1

\frac{- 1}{2} - \frac{1}{2}

\frac{- 1}{2} - \frac{1}{2} = - 1

\frac{- 1}{2} - \frac{1}{2}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 - 1}{2}

Subtract the numbers:

- 1 - 1 = - 2

= \frac{- 2}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{2}{2}

Apply rule

\frac{a}{a} = 1

= - 1

= - 1

= - 1

5 - [63 - 2 - (12 - 8) - 3 + 6]

\frac{1}{3} + \frac{2}{5}

3 (1)^{2} - 24 (1) + 45

3^{3} - 14 \div 2 + 5

[2 \times (- 4)^{2}] + [4 \times (- 2)^{3}] /4