中点 (a,b+3),(a-4,3b)

解答

中点

(a, b + 3), (a - 4, 3 b)

(a - 2, \frac{4 b + 3}{2})

求解步骤

(x_{1}, y_{1}), (x_{2}, y_{2})

的中点:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (a, b + 3), (x_{2}, y_{2}) = (a - 4, 3 b)

= (\frac{a - 4 + a}{2}, \frac{3 b + b + 3}{2})

整理后得

= (a - 2, \frac{4 b + 3}{2})

mi d p o in t (13, 8), (- 6, - 6)

d er i v a t i v e 5 e^{x}

s l o p e 4 x - y + 12 = 0

t an g e n t f (x) = tan (2 x), at x = 0

d er i v a t i v e f (x) = x^{5} - 2 x^{3} + x