polar (2,0)

Lösung

kartesisch zu polar

(2, 0)

(2, 0)

Schritte zur Lösung

r = x^{2} + y^{2}

r = 2^{2} + 0^{2}

2^{2} + 0^{2} = 2

r = 2

θ = arctan (\frac{y}{x})

θ = arctan (\frac{0}{2})

arctan (\frac{0}{2}) = 0

θ = 0

Die Polar Koordinaten von

(2, 0)

(2, 0)

d er i v a t i v e y = 2 x^{2}

d er i v a t i v e x e^{2 x}

d er i v a t i v e f (x) = - 7 x^{\frac{4}{3}} + \frac{4}{x ^{3}}

y^{2} = 4 x

l in e y = 3 x - 5