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tangent f(x)= 1/(x^2)

解答

切线

f (x) = \frac{1}{x ^{2}}

解答

y = - \frac{2}{a _{0}^{3}} x + \frac{3}{a _{0}^{2}}

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, \frac{1}{a _{0}^{2}})

计算

f (x) = \frac{1}{x ^{2}}

的斜率:

\frac{df ( x )}{d x} = - \frac{2}{x ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{2}{a _{0}^{3}}

找到斜率 m=

- \frac{2}{a _{0}^{3}}

且穿过

(a_{0}, \frac{1}{a _{0}^{2}})

的直线:

y = - \frac{2}{a _{0}^{3}} x + \frac{3}{a _{0}^{2}}

y = - \frac{2}{a _{0}^{3}} x + \frac{3}{a _{0}^{2}}

作图

流行的例子

derivative f(x)=x^4

d er i v a t i v e f (x) = x^{4}

derivative x^{11}arccot(x)

d er i v a t i v e x^{11} arccot (x)

中点 (2,-14),(-3,0)

mi d p o in t (2, - 14), (- 3, 0)

s l o p e y = 3 x + 5

中点 (2,4),(2,-7)

mi d p o in t (2, 4), (2, - 7)