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Beliebt Vorkalkül >

mittelpunkt (15,3),(2,-14)

Lösung

mittelpunkt

(15, 3), (2, - 14)

Lösung

(\frac{17}{2}, - \frac{11}{2})

Schritte zur Lösung

Mittelpunkt von

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (15, 3), (x_{2}, y_{2}) = (2, - 14)

= (\frac{2 + 15}{2}, \frac{- 14 + 3}{2})

Fasse zusammen

= (\frac{17}{2}, - \frac{11}{2})

Graph

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d er i v a t i v e f (x) = \frac{x}{x - 2}

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d er i v a t i v e 2 e^{2 x}

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d er i v a t i v e y = x^{3} ln (x)

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d er i v a t i v e y = x^{x}