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Popular >

2tan(x)+sec(x)=0,0<= x<2pi

Solución

2 tan (x) + sec (x) = 0, 0 \leq x < 2 π

Solución

x = \frac{7 π}{6}, x = \frac{11 π}{6}

+1

Pasos de solución

2 tan (x) + sec (x) = 0, 0 \leq x < 2 π

Expresar con seno, coseno

\frac{1 + 2 sin ( x )}{cos ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

1 + 2 sin (x) = 0

Mover

1

al lado derecho

2 sin (x) = - 1

Dividir ambos lados entre

2

sin (x) = - \frac{1}{2}

Soluciones generales para

sin (x) = - \frac{1}{2}

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Soluciones para el rango

0 \leq x < 2 π

x = \frac{7 π}{6}, x = \frac{11 π}{6}

Ejemplos populares

1-sin(x)=sqrt(3)cos(x)

1 - sin (x) = 3 cos (x)

cos(x)-sec(x)=0

cos (x) - sec (x) = 0

2+7cos(x)=4sin^2(x)

2 + 7 cos (x) = 4 sin^{2} (x)

4 arccos (x) = π

2sin^2(x)+2=7cos(x)

2 sin^{2} (x) + 2 = 7 cos (x)