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受欢迎的三角函数 >

2sqrt(2)cos(x)+2=0

解答

22 cos (x) + 2 = 0

解答

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

+1

度数

x = 13 5^{\circ} + 36 0^{\circ} n, x = 22 5^{\circ} + 36 0^{\circ} n

求解步骤

22 cos (x) + 2 = 0

将

2

到右边

22 cos (x) + 2 = 0

两边减去

2

22 cos (x) + 2 - 2 = 0 - 2

化简

22 cos (x) = - 2

22 cos (x) = - 2

两边除以

22

22 cos (x) = - 2

两边除以

22

\frac{2 2 cos ( x )}{2 2} = \frac{- 2}{2 2}

化简

\frac{2 2 cos ( x )}{2 2} = \frac{- 2}{2 2}

化简

\frac{2 2 cos ( x )}{2 2} : cos (x)

\frac{2 2 cos ( x )}{2 2}

数字相除:

\frac{2}{2} = 1

= \frac{2 cos ( x )}{2}

约分:

2

= cos (x)

化简

\frac{- 2}{2 2} : - \frac{2}{2}

\frac{- 2}{2 2}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{2}{2 2}

数字相除:

\frac{2}{2} = 1

= - \frac{1}{2}

- \frac{1}{2}

有理化:

- \frac{2}{2}

- \frac{1}{2}

乘以共轭根式

\frac{2}{2}

= - \frac{1 \cdot 2}{2 2}

1 \cdot 2 = 2

22 = 2

22

使用根式运算法则:

a a = a

22 = 2

= 2

= - \frac{2}{2}

= - \frac{2}{2}

cos (x) = - \frac{2}{2}

cos (x) = - \frac{2}{2}

cos (x) = - \frac{2}{2}

cos (x) = - \frac{2}{2}

的通解

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

作图

流行的例子

8 cos (2 x) = 1

csc (x) = 6

(sin(x))^{sin(x)}=2

(sin (x))^{s i n (x)} = 2

sqrt(cos^2(x)+1/2)+sqrt(sin^2(x)+1/2)=2

cos^{2} (x) + \frac{1}{2} + sin^{2} (x) + \frac{1}{2} = 2

sin^2(x)-2cos(x)-2=0

sin^{2} (x) - 2 cos (x) - 2 = 0