2(sin(x))^2-5cos(x)+1=0

Solución

2 (sin (x))^{2} - 5 cos (x) + 1 = 0

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Pasos de solución

2 (sin (x))^{2} - 5 cos (x) + 1 = 0

Sumar

5 cos (x)

a ambos lados

2 sin^{2} (x) + 1 = 5 cos (x)

Elevar al cuadrado ambos lados

(2 sin^{2} (x) + 1)^{2} = (5 cos (x))^{2}

Restar

(5 cos (x))^{2}

de ambos lados

(2 sin^{2} (x) + 1)^{2} - 25 cos^{2} (x) = 0

Factorizar

(2 sin^{2} (x) + 1)^{2} - 25 cos^{2} (x) : (2 sin^{2} (x) + 1 + 5 cos (x)) (2 sin^{2} (x) + 1 - 5 cos (x))

(2 sin^{2} (x) + 1 + 5 cos (x)) (2 sin^{2} (x) + 1 - 5 cos (x)) = 0

Resolver cada parte por separado

2 sin^{2} (x) + 1 + 5 cos (x) = 0 or 2 sin^{2} (x) + 1 - 5 cos (x) = 0

2 sin^{2} (x) + 1 + 5 cos (x) = 0 : x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

2 sin^{2} (x) + 1 - 5 cos (x) = 0 : x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Combinar toda las soluciones

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn, x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Verificar las soluciones sustituyendo en la ecuación original

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

5 sin (x) cos (x) = 3 cos (x)

3 cos (x) + sin (x) = 2

9 cosh (x) - 5 sinh (x) = 15

3 sin (x) = 3 cos (x)

- 4 sin^{2} (θ) - 7 sin (θ) + 4 = 0