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受欢迎的三角函数 >

0= 1/9 sin(9t)

解答

0 = \frac{1}{9} sin (9 t)

解答

t = \frac{2 πn}{9}, t = \frac{π}{9} + \frac{2 πn}{9}

+1

度数

t = 0^{\circ} + 4 0^{\circ} n, t = 2 0^{\circ} + 4 0^{\circ} n

求解步骤

0 = \frac{1}{9} sin (9 t)

交换两边

\frac{1}{9} sin (9 t) = 0

在两边乘以

9

\frac{1}{9} sin (9 t) = 0

在两边乘以

9

9 \cdot \frac{1}{9} sin (9 t) = 0 \cdot 9

化简

sin (9 t) = 0

sin (9 t) = 0

sin (9 t) = 0

的通解

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

9 t = 0 + 2 πn, 9 t = π + 2 πn

9 t = 0 + 2 πn, 9 t = π + 2 πn

解

9 t = 0 + 2 πn : t = \frac{2 πn}{9}

9 t = 0 + 2 πn

0 + 2 πn = 2 πn

9 t = 2 πn

两边除以

9

9 t = 2 πn

两边除以

9

\frac{9 t}{9} = \frac{2 πn}{9}

化简

t = \frac{2 πn}{9}

t = \frac{2 πn}{9}

解

9 t = π + 2 πn : t = \frac{π}{9} + \frac{2 πn}{9}

9 t = π + 2 πn

两边除以

9

9 t = π + 2 πn

两边除以

9

\frac{9 t}{9} = \frac{π}{9} + \frac{2 πn}{9}

化简

t = \frac{π}{9} + \frac{2 πn}{9}

t = \frac{π}{9} + \frac{2 πn}{9}

t = \frac{2 πn}{9}, t = \frac{π}{9} + \frac{2 πn}{9}

作图

流行的例子

tan (x) = \frac{3}{3}

9cot^2(θ)-25=0

9 cot^{2} (θ) - 25 = 0

7sin(θ)=7cos(2θ)

7 sin (θ) = 7 cos (2 θ)

sin^2(x)-cos^2(x)-cos(x)-1=0

sin^{2} (x) - cos^{2} (x) - cos (x) - 1 = 0

solvefor t,y^{(4)}-81y=sin(t)

so l v e f or t, y^{(4)} - 81 y = sin (t)