cos(θ)=(2sqrt(5))/5

Lösung

cos (θ) = \frac{2 5}{5}

θ = 0.46364 \dots + 2 πn, θ = 2 π - 0.46364 \dots + 2 πn

Grad

θ = 26.56505 \dots^{\circ} + 36 0^{\circ} n, θ = 333.43494 \dots^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (θ) = \frac{2 5}{5}

Wende die Eigenschaften der Trigonometrie an

cos (θ) = \frac{2 5}{5}

Allgemeine Lösung für

cos (θ) = \frac{2 5}{5}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{2 5}{5}) + 2 πn, θ = 2 π - arccos (\frac{2 5}{5}) + 2 πn

θ = arccos (\frac{2 5}{5}) + 2 πn, θ = 2 π - arccos (\frac{2 5}{5}) + 2 πn

Zeige Lösungen in Dezimalform

θ = 0.46364 \dots + 2 πn, θ = 2 π - 0.46364 \dots + 2 πn

cos (x) sin (x) = sin^{2} (x)

- 3 sin (x) + 2 = 0

cot (x) = - 0.6

3 sin (x) - cos (x) = 1

tan (x) = - 0.73