solvefor y,sin(x+y)+sin(y+z)+sin(x+z)=0

Solución

resolver para

y, sin (x + y) + sin (y + z) + sin (x + z) = 0

y = arcsin (- \frac{sin ( x + z )}{2 cos ( \frac{x - z}{2} )}) + 2 πn - \frac{x}{2} - \frac{z}{2}, y = π + arcsin (\frac{sin ( x + z )}{2 cos ( \frac{x - z}{2} )}) + 2 πn - \frac{x}{2} - \frac{z}{2}

Pasos de solución

sin (x + y) + sin (y + z) + sin (x + z) = 0

Re-escribir usando identidades trigonométricas

sin (x + z) + 2 cos (\frac{x - z}{2}) sin (\frac{x + 2 y + z}{2}) = 0

Mover

sin (x + z)

al lado derecho

2 cos (\frac{x - z}{2}) sin (\frac{x + 2 y + z}{2}) = - sin (x + z)

Dividir ambos lados entre

2 cos (\frac{x - z}{2}); x \neq = π + 4 πn + z, x \neq = 3 π + 4 πn + z

sin (\frac{x + 2 y + z}{2}) = - \frac{sin ( x + z )}{2 cos ( \frac{x - z}{2} )}; x \neq = π + 4 πn + z, x \neq = 3 π + 4 πn + z

Aplicar propiedades trigonométricas inversas

\frac{x + 2 y + z}{2} = arcsin (- \frac{sin ( x + z )}{2 cos ( \frac{x - z}{2} )}) + 2 πn, \frac{x + 2 y + z}{2} = π + arcsin (\frac{sin ( x + z )}{2 cos ( \frac{x - z}{2} )}) + 2 πn

Resolver

\frac{x + 2 y + z}{2} = arcsin (- \frac{sin ( x + z )}{2 cos ( \frac{x - z}{2} )}) + 2 πn : y = arcsin (- \frac{sin ( x + z )}{2 cos ( \frac{x - z}{2} )}) + 2 πn - \frac{x}{2} - \frac{z}{2}

Resolver

\frac{x + 2 y + z}{2} = π + arcsin (\frac{sin ( x + z )}{2 cos ( \frac{x - z}{2} )}) + 2 πn : y = π + arcsin (\frac{sin ( x + z )}{2 cos ( \frac{x - z}{2} )}) + 2 πn - \frac{x}{2} - \frac{z}{2}

y = arcsin (- \frac{sin ( x + z )}{2 cos ( \frac{x - z}{2} )}) + 2 πn - \frac{x}{2} - \frac{z}{2}, y = π + arcsin (\frac{sin ( x + z )}{2 cos ( \frac{x - z}{2} )}) + 2 πn - \frac{x}{2} - \frac{z}{2}

2 sin (x) - tan (x) = 0

2 sin^{2} (x) - 13 sin (x) + 6 = 0

2 tan (θ) + 3 = 0

tan (x) = \frac{4}{6}

cos (2 x) = - 2 cos^{2} (x)