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受欢迎的三角函数 >

sinh(-arccosh(2))

解答

sinh (- arccosh (2))

解答

- 3

+1

十进制

- 1.73205 \dots

求解步骤

sinh (- arccosh (2))

利用以下特性:

sinh (- x) = - sinh (x)

sinh (- arccosh (2)) = - sinh (arccosh (2))

= - sinh (arccosh (2))

使用三角恒等式改写:

sinh (arccosh (2)) = \frac{e ^{2 arccosh (2)} - 1}{2 e ^{arccosh (2)}}

sinh (arccosh (2))

使用双曲函数恒等式:

sinh (x) = \frac{e ^{x} - e ^{- x}}{2}

= \frac{e ^{arccosh (2)} - e ^{- arccosh (2)}}{2}

\frac{e ^{arccosh (2)} - e ^{- arccosh (2)}}{2} = \frac{e ^{2 arccosh (2)} - 1}{2 e ^{arccosh (2)}}

\frac{e ^{arccosh (2)} - e ^{- arccosh (2)}}{2}

使用指数法则:

a^{- b} = \frac{1}{a ^{b}}

= \frac{e ^{arccosh (2)} - \frac{1}{e ^{arccosh (2)}}}{2}

化简

e^{arccosh (2)} - \frac{1}{e ^{arccosh (2)}} : \frac{e ^{2 arccosh (2)} - 1}{e ^{arccosh (2)}}

e^{arccosh (2)} - \frac{1}{e ^{arccosh (2)}}

将项转换为分式:

e^{arccosh (2)} = \frac{e ^{arccosh (2)} e ^{arccosh (2)}}{e ^{arccosh (2)}}

= \frac{e ^{arccosh (2)} e ^{arccosh (2)}}{e ^{arccosh (2)}} - \frac{1}{e ^{arccosh (2)}}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{e ^{arccosh (2)} e ^{arccosh (2)} - 1}{e ^{arccosh (2)}}

e^{arccosh (2)} e^{arccosh (2)} - 1 = e^{2 arccosh (2)} - 1

e^{arccosh (2)} e^{arccosh (2)} - 1

e^{arccosh (2)} e^{arccosh (2)} = e^{2 arccosh (2)}

e^{arccosh (2)} e^{arccosh (2)}

使用指数法则:

a^{b} \cdot a^{c} = a^{b + c}

e^{arccosh (2)} e^{arccosh (2)} = e^{arccosh (2) + arccosh (2)}

= e^{arccosh (2) + arccosh (2)}

同类项相加:

arccosh (2) + arccosh (2) = 2 arccosh (2)

= e^{2 arccosh (2)}

= e^{2 arccosh (2)} - 1

= \frac{e ^{2 arccosh (2)} - 1}{e ^{arccosh (2)}}

= \frac{\frac{e ^{2 arccosh (2)} - 1}{e ^{arccosh (2)}}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{e ^{2 arccosh (2)} - 1}{e ^{arccosh (2)} \cdot 2}

= \frac{e ^{2 arccosh (2)} - 1}{2 e ^{arccosh (2)}}

= - \frac{e ^{2 arccosh (2)} - 1}{2 e ^{arccosh (2)}}

使用三角恒等式改写:

arccosh (2) = ln (2 + 3)

arccosh (2)

使用双曲函数恒等式:

arccosh (x) = ln (x + x^{2} - 1)

= ln (2 + 2^{2} - 1)

化简

= ln (2 + 3)

= - \frac{e ^{2 l n (2 + 3)} - 1}{2 e ^{l n (2 + 3)}}

化简

- \frac{e ^{2 l n (2 + 3)} - 1}{2 e ^{l n (2 + 3)}} : - 3

- \frac{e ^{2 l n (2 + 3)} - 1}{2 e ^{l n (2 + 3)}}

e^{l n (2 + 3)} = 2 + 3

e^{l n (2 + 3)}

使用对数计算法则:

a^{l o g_{a} (b)} = b

= 2 + 3

= - \frac{e ^{2 l n (2 + 3)} - 1}{2 ( 2 + 3 )}

e^{2 l n (2 + 3)} = (2 + 3)^{2}

e^{2 l n (2 + 3)}

使用指数法则:

a^{b c} = (a^{b})^{c}

= (e^{l n (2 + 3)})^{2}

使用对数计算法则:

a^{l o g_{a} (b)} = b

e^{l n (2 + 3)} = 2 + 3

= (2 + 3)^{2}

= - \frac{( 2 + 3 ) ^{2} - 1}{2 ( 2 + 3 )}

化简

- \frac{( 2 + 3 ) ^{2} - 1}{2 ( 2 + 3 )}

乘开

(2 + 3)^{2} - 1 : 6 + 43

(2 + 3)^{2} - 1

(2 + 3)^{2} : 7 + 43

使用完全平方公式:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = 2, b = 3

= 2^{2} + 2 \cdot 23 + (3)^{2}

化简

2^{2} + 2 \cdot 23 + (3)^{2} : 7 + 43

2^{2} + 2 \cdot 23 + (3)^{2}

2^{2} = 4

2^{2}

2^{2} = 4

= 4

2 \cdot 23 = 43

2 \cdot 23

数字相乘:

2 \cdot 2 = 4

= 43

(3)^{2} = 3

(3)^{2}

使用根式运算法则:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

使用指数法则:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

约分:

2

= 1

= 3

= 4 + 43 + 3

数字相加:

4 + 3 = 7

= 7 + 43

= 7 + 43

= 7 + 43 - 1

数字相减:

7 - 1 = 6

= 6 + 43

= - \frac{6 + 4 3}{2 ( 2 + 3 )}

消掉

\frac{6 + 4 3}{2 ( 2 + 3 )} : 3

\frac{6 + 4 3}{2 ( 2 + 3 )}

分解

6 + 43 : 2 (3 + 23)

6 + 43

改写为

= 2 \cdot 3 + 2 \cdot 23

因式分解出通项

2

= 2 (3 + 23)

= \frac{2 ( 3 + 2 3 )}{2 ( 2 + 3 )}

数字相除:

\frac{2}{2} = 1

= \frac{3 + 2 3}{( 2 + 3 )}

分解

3 + 23 : 3 (3 + 2)

3 + 23

3 = 33

= 33 + 23

因式分解出通项

3

= 3 (3 + 2)

= \frac{3 ( 3 + 2 )}{( 2 + 3 )}

约分:

3 + 2

= 3

= - 3

= - 3

= - 3

流行的例子

sin(pi/9)-sin((2pi)/9)-sin((3pi)/9)+sin((4pi)/9)

sin (\frac{π}{9}) - sin (\frac{2 π}{9}) - sin (\frac{3 π}{9}) + sin (\frac{4 π}{9})

- 3 cos (\frac{1}{2} \cdot 0)

sin (π - \frac{π}{3})

sin (2) \cdot sin (3)

arccos(0.974631846)

arccos (0.974631846)