sec(900)

Lösung

sec (90 0^{\circ})

- 1

Schritte zur Lösung

sec (90 0^{\circ})

sec (90 0^{\circ}) = sec (18 0^{\circ})

sec (90 0^{\circ})

Schreibe

90 0^{\circ}

um:

36 0^{\circ} \cdot 2 + 18 0^{\circ}

= sec (36 0^{\circ} 2 + 18 0^{\circ})

Verwende die Periodizität von

sec

sec (x + 36 0^{\circ} \cdot k) = sec (x)

sec (36 0^{\circ} \cdot 2 + 18 0^{\circ}) = sec (18 0^{\circ})

= sec (18 0^{\circ})

= sec (18 0^{\circ})

Verwende die folgende triviale Identität:

sec (18 0^{\circ}) = (- 1)

sec (18 0^{\circ})

sec (x)

Periodizitätstabelle mit

36 0^{\circ} n

Zyklus:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

= (- 1)

= - 1

\frac{600}{sin ( 4 5 ^{\circ} )}

sin (4 (\frac{π}{4}))

\frac{sin ( 2 0 ^{\circ} )}{8}

cos (\frac{6 π}{8})

sin (15 9^{\circ})