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受欢迎的三角函数 >

sinh((pii)/2)

解答

sinh (\frac{πi}{2})

解答

i sin (\frac{π}{2})

求解步骤

sinh (\frac{πi}{2})

使用双曲函数恒等式:

sinh (x) = \frac{e ^{x} - e ^{- x}}{2}

= \frac{e ^{\frac{iπ}{2}} - e ^{- \frac{iπ}{2}}}{2}

化简

\frac{e ^{\frac{iπ}{2}} - e ^{- \frac{iπ}{2}}}{2} : \frac{- cos ( - \frac{π}{2} ) + cos ( \frac{π}{2} )}{2} + i \frac{- sin ( - \frac{π}{2} ) + sin ( \frac{π}{2} )}{2}

\frac{e ^{\frac{iπ}{2}} - e ^{- \frac{iπ}{2}}}{2}

e^{\frac{iπ}{2}} - e^{- \frac{iπ}{2}} = cos (\frac{π}{2}) + i sin (\frac{π}{2}) - (cos (- \frac{π}{2}) + i sin (- \frac{π}{2}))

e^{\frac{iπ}{2}} - e^{- \frac{iπ}{2}}

使用虚数运算法则:

e^{ia} = cos (a) + i sin (a)

= cos (\frac{π}{2}) + i sin (\frac{π}{2}) - e^{- \frac{iπ}{2}}

使用虚数运算法则:

e^{ia} = cos (a) + i sin (a)

= cos (\frac{π}{2}) + i sin (\frac{π}{2}) - (cos (- \frac{π}{2}) + i sin (- \frac{π}{2}))

= \frac{cos ( \frac{π}{2} ) + i sin ( \frac{π}{2} ) - ( cos ( - \frac{π}{2} ) + i sin ( - \frac{π}{2} ) )}{2}

乘开

cos (\frac{π}{2}) + sin (\frac{π}{2}) i - (cos (- \frac{π}{2}) + sin (- \frac{π}{2}) i) : cos (\frac{π}{2}) + sin (\frac{π}{2}) i - cos (- \frac{π}{2}) - sin (- \frac{π}{2}) i

cos (\frac{π}{2}) + sin (\frac{π}{2}) i - (cos (- \frac{π}{2}) + sin (- \frac{π}{2}) i)

= cos (\frac{π}{2}) + i sin (\frac{π}{2}) - (cos (- \frac{π}{2}) + i sin (- \frac{π}{2}))

- (cos (- \frac{π}{2}) + sin (- \frac{π}{2}) i) : - cos (- \frac{π}{2}) - sin (- \frac{π}{2}) i

- (cos (- \frac{π}{2}) + sin (- \frac{π}{2}) i)

打开括号

= - (cos (- \frac{π}{2})) - (sin (- \frac{π}{2}) i)

使用加减运算法则

+ (- a) = - a

= - cos (- \frac{π}{2}) - sin (- \frac{π}{2}) i

= cos (\frac{π}{2}) + sin (\frac{π}{2}) i - cos (- \frac{π}{2}) - sin (- \frac{π}{2}) i

= \frac{cos ( \frac{π}{2} ) + i sin ( \frac{π}{2} ) - cos ( - \frac{π}{2} ) - i sin ( - \frac{π}{2} )}{2}

将

\frac{cos ( \frac{π}{2} ) + sin ( \frac{π}{2} ) i - cos ( - \frac{π}{2} ) - sin ( - \frac{π}{2} ) i}{2}

改写成标准复数形式:

\frac{cos ( \frac{π}{2} ) - cos ( - \frac{π}{2} )}{2} + \frac{sin ( \frac{π}{2} ) - sin ( - \frac{π}{2} )}{2} i

\frac{cos ( \frac{π}{2} ) + sin ( \frac{π}{2} ) i - cos ( - \frac{π}{2} ) - sin ( - \frac{π}{2} ) i}{2}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{cos ( \frac{π}{2} ) + sin ( \frac{π}{2} ) i - cos ( - \frac{π}{2} ) - sin ( - \frac{π}{2} ) i}{2} = \frac{cos ( \frac{π}{2} )}{2} + \frac{sin ( \frac{π}{2} ) i}{2} - \frac{cos ( - \frac{π}{2} )}{2} - \frac{sin ( - \frac{π}{2} ) i}{2}

= \frac{cos ( \frac{π}{2} )}{2} + \frac{i sin ( \frac{π}{2} )}{2} - \frac{cos ( - \frac{π}{2} )}{2} - \frac{i sin ( - \frac{π}{2} )}{2}

对同类项分组

= \frac{cos ( \frac{π}{2} )}{2} + \frac{i sin ( \frac{π}{2} )}{2} - \frac{cos ( - \frac{π}{2} )}{2} - \frac{i sin ( - \frac{π}{2} )}{2}

将复数的实部和虚部分组

= (\frac{cos ( \frac{π}{2} )}{2} - \frac{cos ( - \frac{π}{2} )}{2}) + (\frac{sin ( \frac{π}{2} )}{2} - \frac{sin ( - \frac{π}{2} )}{2}) i

\frac{sin ( \frac{π}{2} )}{2} - \frac{sin ( - \frac{π}{2} )}{2} = \frac{sin ( \frac{π}{2} ) - sin ( - \frac{π}{2} )}{2}

\frac{sin ( \frac{π}{2} )}{2} - \frac{sin ( - \frac{π}{2} )}{2}

使用法则

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{sin ( \frac{π}{2} ) - sin ( - \frac{π}{2} )}{2}

= (\frac{cos ( \frac{π}{2} )}{2} - \frac{cos ( - \frac{π}{2} )}{2}) + \frac{sin ( \frac{π}{2} ) - sin ( - \frac{π}{2} )}{2} i

\frac{cos ( \frac{π}{2} )}{2} - \frac{cos ( - \frac{π}{2} )}{2} = \frac{cos ( \frac{π}{2} ) - cos ( - \frac{π}{2} )}{2}

\frac{cos ( \frac{π}{2} )}{2} - \frac{cos ( - \frac{π}{2} )}{2}

使用法则

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{cos ( \frac{π}{2} ) - cos ( - \frac{π}{2} )}{2}

= \frac{cos ( \frac{π}{2} ) - cos ( - \frac{π}{2} )}{2} + \frac{sin ( \frac{π}{2} ) - sin ( - \frac{π}{2} )}{2} i

= \frac{cos ( \frac{π}{2} ) - cos ( - \frac{π}{2} )}{2} + \frac{sin ( \frac{π}{2} ) - sin ( - \frac{π}{2} )}{2} i

= \frac{- cos ( - \frac{π}{2} ) + cos ( \frac{π}{2} )}{2} + i \frac{- sin ( - \frac{π}{2} ) + sin ( \frac{π}{2} )}{2}

利用以下特性:

sin (- x) = - sin (x)

sin (- \frac{π}{2}) = - sin (\frac{π}{2})

= \frac{- cos ( - \frac{π}{2} ) + cos ( \frac{π}{2} )}{2} + i \frac{- ( - sin ( \frac{π}{2} ) ) + sin ( \frac{π}{2} )}{2}

利用以下特性:

cos (- x) = cos (x)

cos (- \frac{π}{2}) = cos (\frac{π}{2})

= \frac{- cos ( \frac{π}{2} ) + cos ( \frac{π}{2} )}{2} + i \frac{- ( - sin ( \frac{π}{2} ) ) + sin ( \frac{π}{2} )}{2}

化简

= i sin (\frac{π}{2})

流行的例子

sin (\frac{29 π}{4})

(150)/(sin(43))

\frac{150}{sin ( 4 3 ^{\circ} )}

0.96 \cdot sin (3 0^{\circ})

cos (- 96 0^{\circ})

cos((3pi)/4)-i*sin((3pi)/4)

cos (\frac{3 π}{4}) - i \cdot sin (\frac{3 π}{4})