zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

3cos^2(x)+sin^2(x)+5sin(x)=0

解答

3 cos^{2} (x) + sin^{2} (x) + 5 sin (x) = 0

解答

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

+1

度数

x = 21 0^{\circ} + 36 0^{\circ} n, x = 33 0^{\circ} + 36 0^{\circ} n

求解步骤

3 cos^{2} (x) + sin^{2} (x) + 5 sin (x) = 0

使用三角恒等式改写

sin^{2} (x) + 3 cos^{2} (x) + 5 sin (x)

使用毕达哥拉斯恒等式:

cos^{2} (x) + sin^{2} (x) = 1

cos^{2} (x) = 1 - sin^{2} (x)

= sin^{2} (x) + 3 (1 - sin^{2} (x)) + 5 sin (x)

化简

sin^{2} (x) + 3 (1 - sin^{2} (x)) + 5 sin (x) : - 2 sin^{2} (x) + 5 sin (x) + 3

sin^{2} (x) + 3 (1 - sin^{2} (x)) + 5 sin (x)

乘开

3 (1 - sin^{2} (x)) : 3 - 3 sin^{2} (x)

3 (1 - sin^{2} (x))

使用分配律:

a (b - c) = ab - a c

a = 3, b = 1, c = sin^{2} (x)

= 3 \cdot 1 - 3 sin^{2} (x)

数字相乘:

3 \cdot 1 = 3

= 3 - 3 sin^{2} (x)

= sin^{2} (x) + 3 - 3 sin^{2} (x) + 5 sin (x)

化简

sin^{2} (x) + 3 - 3 sin^{2} (x) + 5 sin (x) : - 2 sin^{2} (x) + 5 sin (x) + 3

sin^{2} (x) + 3 - 3 sin^{2} (x) + 5 sin (x)

对同类项分组

= sin^{2} (x) - 3 sin^{2} (x) + 5 sin (x) + 3

同类项相加:

sin^{2} (x) - 3 sin^{2} (x) = - 2 sin^{2} (x)

= - 2 sin^{2} (x) + 5 sin (x) + 3

= - 2 sin^{2} (x) + 5 sin (x) + 3

= - 2 sin^{2} (x) + 5 sin (x) + 3

3 - 2 sin^{2} (x) + 5 sin (x) = 0

用替代法求解

3 - 2 sin^{2} (x) + 5 sin (x) = 0

令

: sin (x) = u

3 - 2 u^{2} + 5 u = 0

3 - 2 u^{2} + 5 u = 0 : u = - \frac{1}{2}, u = 3

3 - 2 u^{2} + 5 u = 0

改写成标准形式

a x^{2} + b x + c = 0

- 2 u^{2} + 5 u + 3 = 0

使用求根公式求解

- 2 u^{2} + 5 u + 3 = 0

二次方程求根公式:

若

a = - 2, b = 5, c = 3

u_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 2 ) \cdot 3}{2 ( - 2 )}

u_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 2 ) \cdot 3}{2 ( - 2 )}

5^{2} - 4 (- 2) \cdot 3 = 7

5^{2} - 4 (- 2) \cdot 3

使用法则

- (- a) = a

= 5^{2} + 4 \cdot 2 \cdot 3

数字相乘:

4 \cdot 2 \cdot 3 = 24

= 5^{2} + 24

5^{2} = 25

= 25 + 24

数字相加:

25 + 24 = 49

= 49

因式分解数字:

49 = 7^{2}

= 7^{2}

使用根式运算法则:

n a^{n} = a

7^{2} = 7

= 7

u_{1, 2} = \frac{- 5 \pm 7}{2 ( - 2 )}

将解分隔开

u_{1} = \frac{- 5 + 7}{2 ( - 2 )}, u_{2} = \frac{- 5 - 7}{2 ( - 2 )}

u = \frac{- 5 + 7}{2 ( - 2 )} : - \frac{1}{2}

\frac{- 5 + 7}{2 ( - 2 )}

去除括号:

(- a) = - a

= \frac{- 5 + 7}{- 2 \cdot 2}

数字相加/相减:

- 5 + 7 = 2

= \frac{2}{- 2 \cdot 2}

数字相乘:

2 \cdot 2 = 4

= \frac{2}{- 4}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{2}{4}

约分:

2

= - \frac{1}{2}

u = \frac{- 5 - 7}{2 ( - 2 )} : 3

\frac{- 5 - 7}{2 ( - 2 )}

去除括号:

(- a) = - a

= \frac{- 5 - 7}{- 2 \cdot 2}

数字相减:

- 5 - 7 = - 12

= \frac{- 12}{- 2 \cdot 2}

数字相乘:

2 \cdot 2 = 4

= \frac{- 12}{- 4}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{12}{4}

数字相除:

\frac{12}{4} = 3

= 3

二次方程组的解是:

u = - \frac{1}{2}, u = 3

u = sin (x)

代回

sin (x) = - \frac{1}{2}, sin (x) = 3

sin (x) = - \frac{1}{2}, sin (x) = 3

sin (x) = - \frac{1}{2} : x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

sin (x) = - \frac{1}{2}

sin (x) = - \frac{1}{2}

的通解

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

sin (x) = 3 :

无解

sin (x) = 3

- 1 \leq sin (x) \leq 1

无解

合并所有解

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

作图

流行的例子

2tan(x)=5sin(x)

2 tan (x) = 5 sin (x)

5 cot (x) = 2

tan(3x+(3pi)/4)=1

tan (3 x + \frac{3 π}{4}) = 1

2 sin (3 x + 1) = 1

tan (2 x - 5) = 1