cos(2x)=((6k-9))/9

Solución

cos (2 x) = \frac{( 6 k - 9 )}{9}

x = \frac{arccos ( \frac{2 k - 3}{3} )}{2} + πn, x = - \frac{arccos ( \frac{2 k - 3}{3} )}{2} + πn

Pasos de solución

cos (2 x) = \frac{( 6 k - 9 )}{9}

Simplificar

\frac{6 k - 9}{9} : \frac{2 k - 3}{3}

Aplicar propiedades trigonométricas inversas

2 x = arccos (\frac{2 k - 3}{3}) + 2 πn, 2 x = - arccos (\frac{2 k - 3}{3}) + 2 πn

Resolver

2 x = arccos (\frac{2 k - 3}{3}) + 2 πn : x = \frac{arccos ( \frac{2 k - 3}{3} )}{2} + πn

Resolver

2 x = - arccos (\frac{2 k - 3}{3}) + 2 πn : x = - \frac{arccos ( \frac{2 k - 3}{3} )}{2} + πn

x = \frac{arccos ( \frac{2 k - 3}{3} )}{2} + πn, x = - \frac{arccos ( \frac{2 k - 3}{3} )}{2} + πn

csc (x) = 1 + cot (x)

6 sin^{2} (x) = 5 sin (x)

cos (π x) = 1

\frac{( 3 )}{( cos ( x ) )} = 8 - 5 tan (x)

x, π + 3 arccos (x + 1) = 0