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인기 있는 삼각법 >

tan^2(x)-4sin(x)+4=0

해법

tan^{2} (x) - 4 sin (x) + 4 = 0

해법

솔루션 없음 x \in R

솔루션 단계

tan^{2} (x) - 4 sin (x) + 4 = 0

더하다

4 sin (x)

양쪽으로

tan^{2} (x) + 4 = 4 sin (x)

양쪽을 제곱

(tan^{2} (x) + 4)^{2} = (4 sin (x))^{2}

빼다

(4 sin (x))^{2}

양쪽에서

(tan^{2} (x) + 4)^{2} - 16 sin^{2} (x) = 0

삼각성을 사용하여 다시 쓰기

(4 + tan^{2} (x))^{2} - 16 sin^{2} (x)

기본 삼각형 항등식 사용:

tan (x) = \frac{sin ( x )}{cos ( x )}

= (4 + (\frac{sin ( x )}{cos ( x )})^{2})^{2} - 16 sin^{2} (x)

지수 규칙 적용:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= (4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )})^{2} - 16 sin^{2} (x)

(4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )})^{2} - 16 sin^{2} (x) = 0

(4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )})^{2} - 16 sin^{2} (x)

요인:

(4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )} + 4 sin (x)) (4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )} - 4 sin (x))

(4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )})^{2} - 16 sin^{2} (x)

16 sin^{2} (x) (2^{2} sin (x))^{2}

로 다시 씁니다

16 sin^{2} (x)

지수 규칙 적용:

a^{b c} = (a^{b})^{c}

16 = (2^{2})^{2}

= (2^{2})^{2} sin^{2} (x)

지수 규칙 적용:

a^{m} b^{m} = (ab)^{m}

(2^{2})^{2} sin^{2} (x) = (2^{2} sin (x))^{2}

= (2^{2} sin (x))^{2}

= (4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )})^{2} - (2^{2} sin (x))^{2}

두 제곱 공식의 차이 적용:

x^{2} - y^{2} = (x + y) (x - y)

(4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )})^{2} - (2^{2} sin (x))^{2} = ((4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )}) + 2^{2} sin (x)) ((4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )}) - 2^{2} sin (x))

= ((4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )}) + 2^{2} sin (x)) ((4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )}) - 2^{2} sin (x))

다듬다

= (\frac{sin ^{2} ( x )}{cos ^{2} ( x )} + 4 sin (x) + 4) (\frac{sin ^{2} ( x )}{cos ^{2} ( x )} - 4 sin (x) + 4)

(4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )} + 4 sin (x)) (4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )} - 4 sin (x)) = 0

각 부분을 개별적으로 해결

4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )} + 4 sin (x) = 0 or 4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )} - 4 sin (x) = 0

4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )} + 4 sin (x) = 0 :

해결책 없음

4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )} + 4 sin (x) = 0

4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )} + 4 sin (x)

단순화하세요:

\frac{4 cos ^{2} ( x ) + sin ^{2} ( x ) + 4 cos ^{2} ( x ) sin ( x )}{cos ^{2} ( x )}

4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )} + 4 sin (x)

요소를 분수로 변환:

4 = \frac{4 cos ^{2} ( x )}{cos ^{2} ( x )}, 4 sin (x) = \frac{4 sin ( x ) cos ^{2} ( x )}{cos ^{2} ( x )}

= \frac{4 cos ^{2} ( x )}{cos ^{2} ( x )} + \frac{sin ^{2} ( x )}{cos ^{2} ( x )} + \frac{4 sin ( x ) cos ^{2} ( x )}{cos ^{2} ( x )}

분모가 같기 때문에, 분수를 합친다:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{4 cos ^{2} ( x ) + sin ^{2} ( x ) + 4 sin ( x ) cos ^{2} ( x )}{cos ^{2} ( x )}

\frac{4 cos ^{2} ( x ) + sin ^{2} ( x ) + 4 cos ^{2} ( x ) sin ( x )}{cos ^{2} ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

4 cos^{2} (x) + sin^{2} (x) + 4 cos^{2} (x) sin (x) = 0

삼각성을 사용하여 다시 쓰기

sin^{2} (x) + 4 cos^{2} (x) + 4 cos^{2} (x) sin (x)

피타고라스 정체성 사용:

cos^{2} (x) + sin^{2} (x) = 1

cos^{2} (x) = 1 - sin^{2} (x)

= sin^{2} (x) + 4 (1 - sin^{2} (x)) + 4 (1 - sin^{2} (x)) sin (x)

sin^{2} (x) + 4 (1 - sin^{2} (x)) + 4 (1 - sin^{2} (x)) sin (x)

간소화하다 :

- 3 sin^{2} (x) + 4 sin (x) - 4 sin^{3} (x) + 4

sin^{2} (x) + 4 (1 - sin^{2} (x)) + 4 (1 - sin^{2} (x)) sin (x)

= sin^{2} (x) + 4 (1 - sin^{2} (x)) + 4 sin (x) (1 - sin^{2} (x))

4 (1 - sin^{2} (x))

확대한다:

4 - 4 sin^{2} (x)

4 (1 - sin^{2} (x))

분배 법칙 적용:

a (b - c) = ab - a c

a = 4, b = 1, c = sin^{2} (x)

= 4 \cdot 1 - 4 sin^{2} (x)

숫자를 곱하시오:

4 \cdot 1 = 4

= 4 - 4 sin^{2} (x)

= sin^{2} (x) + 4 - 4 sin^{2} (x) + 4 (1 - sin^{2} (x)) sin (x)

4 sin (x) (1 - sin^{2} (x))

확대한다:

4 sin (x) - 4 sin^{3} (x)

4 sin (x) (1 - sin^{2} (x))

분배 법칙 적용:

a (b - c) = ab - a c

a = 4 sin (x), b = 1, c = sin^{2} (x)

= 4 sin (x) \cdot 1 - 4 sin (x) sin^{2} (x)

= 4 \cdot 1 \cdot sin (x) - 4 sin^{2} (x) sin (x)

4 \cdot 1 \cdot sin (x) - 4 sin^{2} (x) sin (x)

단순화하세요:

4 sin (x) - 4 sin^{3} (x)

4 \cdot 1 \cdot sin (x) - 4 sin^{2} (x) sin (x)

4 \cdot 1 \cdot sin (x) = 4 sin (x)

4 \cdot 1 \cdot sin (x)

숫자를 곱하시오:

4 \cdot 1 = 4

= 4 sin (x)

4 sin^{2} (x) sin (x) = 4 sin^{3} (x)

4 sin^{2} (x) sin (x)

지수 규칙 적용:

a^{b} \cdot a^{c} = a^{b + c}

sin^{2} (x) sin (x) = sin^{2 + 1} (x)

= 4 sin^{2 + 1} (x)

숫자 추가:

2 + 1 = 3

= 4 sin^{3} (x)

= 4 sin (x) - 4 sin^{3} (x)

= 4 sin (x) - 4 sin^{3} (x)

= sin^{2} (x) + 4 - 4 sin^{2} (x) + 4 sin (x) - 4 sin^{3} (x)

sin^{2} (x) + 4 - 4 sin^{2} (x) + 4 sin (x) - 4 sin^{3} (x)

단순화하세요:

- 3 sin^{2} (x) + 4 sin (x) - 4 sin^{3} (x) + 4

sin^{2} (x) + 4 - 4 sin^{2} (x) + 4 sin (x) - 4 sin^{3} (x)

집단적 용어

= sin^{2} (x) - 4 sin^{2} (x) + 4 sin (x) - 4 sin^{3} (x) + 4

유사 요소 추가:

sin^{2} (x) - 4 sin^{2} (x) = - 3 sin^{2} (x)

= - 3 sin^{2} (x) + 4 sin (x) - 4 sin^{3} (x) + 4

= - 3 sin^{2} (x) + 4 sin (x) - 4 sin^{3} (x) + 4

= - 3 sin^{2} (x) + 4 sin (x) - 4 sin^{3} (x) + 4

4 - 3 sin^{2} (x) + 4 sin (x) - 4 sin^{3} (x) = 0

대체로 해결

4 - 3 sin^{2} (x) + 4 sin (x) - 4 sin^{3} (x) = 0

하게:

sin (x) = u

4 - 3 u^{2} + 4 u - 4 u^{3} = 0

4 - 3 u^{2} + 4 u - 4 u^{3} = 0 : u \approx 1.06659 \dots

4 - 3 u^{2} + 4 u - 4 u^{3} = 0

표준 양식으로 작성

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

- 4 u^{3} - 3 u^{2} + 4 u + 4 = 0

다음을 위한 하나의 솔루션 찾기

- 4 u^{3} - 3 u^{2} + 4 u + 4 = 0

뉴턴-랩슨을 이용하여:

u \approx 1.06659 \dots

- 4 u^{3} - 3 u^{2} + 4 u + 4 = 0

뉴턴-랩슨 근사 정의

f (u) = - 4 u^{3} - 3 u^{2} + 4 u + 4

f^{^{'}} (u)

찾다 :

- 12 u^{2} - 6 u + 4

\frac{d}{d u} (- 4 u^{3} - 3 u^{2} + 4 u + 4)

합계/차이 규칙 적용:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d u} (4 u^{3}) - \frac{d}{d u} (3 u^{2}) + \frac{d}{d u} (4 u) + \frac{d}{d u} (4)

\frac{d}{d u} (4 u^{3}) = 12 u^{2}

\frac{d}{d u} (4 u^{3})

정수를 빼라:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d u} (u^{3})

전원 규칙을 적용합니다:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 \cdot 3 u^{3 - 1}

단순화

= 12 u^{2}

\frac{d}{d u} (3 u^{2}) = 6 u

\frac{d}{d u} (3 u^{2})

정수를 빼라:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d u} (u^{2})

전원 규칙을 적용합니다:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 \cdot 2 u^{2 - 1}

단순화

= 6 u

\frac{d}{d u} (4 u) = 4

\frac{d}{d u} (4 u)

정수를 빼라:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d u}{d u}

공통 도함수 적용:

\frac{d u}{d u} = 1

= 4 \cdot 1

단순화

= 4

\frac{d}{d u} (4) = 0

\frac{d}{d u} (4)

상수의 도함수:

\frac{d}{d x} (a) = 0

= 0

= - 12 u^{2} - 6 u + 4 + 0

단순화

= - 12 u^{2} - 6 u + 4

렛

u_{0} = 1

계산하다

u_{n + 1}

까지

Δ u_{n + 1} < 0.000001

u_{1} = 1.07142 \dots : Δ u_{1} = 0.07142 \dots

f (u_{0}) = - 4 \cdot 1^{3} - 3 \cdot 1^{2} + 4 \cdot 1 + 4 = 1

f^{^{'}} (u_{0}) = - 12 \cdot 1^{2} - 6 \cdot 1 + 4 = - 14

u_{1} = 1.07142 \dots

Δ u_{1} = ∣ 1.07142 \dots - 1 ∣ = 0.07142 \dots

Δ u_{1} = 0.07142 \dots

u_{2} = 1.06661 \dots : Δ u_{2} = 0.00481 \dots

f (u_{1}) = - 4 \cdot 1.07142 \dots^{3} - 3 \cdot 1.07142 \dots^{2} + 4 \cdot 1.07142 \dots + 4 = - 0.07798 \dots

f^{^{'}} (u_{1}) = - 12 \cdot 1.07142 \dots^{2} - 6 \cdot 1.07142 \dots + 4 = - 16.20408 \dots

u_{2} = 1.06661 \dots

Δ u_{2} = ∣ 1.06661 \dots - 1.07142 \dots ∣ = 0.00481 \dots

Δ u_{2} = 0.00481 \dots

u_{3} = 1.06659 \dots : Δ u_{3} = 0.00002 \dots

f (u_{2}) = - 4 \cdot 1.06661 \dots^{3} - 3 \cdot 1.06661 \dots^{2} + 4 \cdot 1.06661 \dots + 4 = - 0.00036 \dots

f^{^{'}} (u_{2}) = - 12 \cdot 1.06661 \dots^{2} - 6 \cdot 1.06661 \dots + 4 = - 16.05172 \dots

u_{3} = 1.06659 \dots

Δ u_{3} = ∣ 1.06659 \dots - 1.06661 \dots ∣ = 0.00002 \dots

Δ u_{3} = 0.00002 \dots

u_{4} = 1.06659 \dots : Δ u_{4} = 5.14172 E - 10

f (u_{3}) = - 4 \cdot 1.06659 \dots^{3} - 3 \cdot 1.06659 \dots^{2} + 4 \cdot 1.06659 \dots + 4 = - 8.25297 E - 9

f^{^{'}} (u_{3}) = - 12 \cdot 1.06659 \dots^{2} - 6 \cdot 1.06659 \dots + 4 = - 16.05100 \dots

u_{4} = 1.06659 \dots

Δ u_{4} = ∣ 1.06659 \dots - 1.06659 \dots ∣ = 5.14172 E - 10

Δ u_{4} = 5.14172 E - 10

u \approx 1.06659 \dots

긴 나눗셈 적용:

\frac{- 4 u ^{3} - 3 u ^{2} + 4 u + 4}{u - 1.06659 \dots} = - 4 u^{2} - 7.26637 \dots u - 3.75025 \dots

- 4 u^{2} - 7.26637 \dots u - 3.75025 \dots \approx 0

다음을 위한 하나의 솔루션 찾기

- 4 u^{2} - 7.26637 \dots u - 3.75025 \dots = 0

뉴턴-랩슨을 이용하여:

솔루션 없음

u \in R

- 4 u^{2} - 7.26637 \dots u - 3.75025 \dots = 0

뉴턴-랩슨 근사 정의

f (u) = - 4 u^{2} - 7.26637 \dots u - 3.75025 \dots

f^{^{'}} (u)

찾다 :

- 8 u - 7.26637 \dots

\frac{d}{d u} (- 4 u^{2} - 7.26637 \dots u - 3.75025 \dots)

합계/차이 규칙 적용:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d u} (4 u^{2}) - \frac{d}{d u} (7.26637 \dots u) - \frac{d}{d u} (3.75025 \dots)

\frac{d}{d u} (4 u^{2}) = 8 u

\frac{d}{d u} (4 u^{2})

정수를 빼라:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d u} (u^{2})

전원 규칙을 적용합니다:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 \cdot 2 u^{2 - 1}

단순화

= 8 u

\frac{d}{d u} (7.26637 \dots u) = 7.26637 \dots

\frac{d}{d u} (7.26637 \dots u)

정수를 빼라:

(a \cdot f)^{'} = a \cdot f^{'}

= 7.26637 \dots \frac{d u}{d u}

공통 도함수 적용:

\frac{d u}{d u} = 1

= 7.26637 \dots \cdot 1

단순화

= 7.26637 \dots

\frac{d}{d u} (3.75025 \dots) = 0

\frac{d}{d u} (3.75025 \dots)

상수의 도함수:

\frac{d}{d x} (a) = 0

= 0

= - 8 u - 7.26637 \dots - 0

단순화

= - 8 u - 7.26637 \dots

렛

u_{0} = - 1

계산하다

u_{n + 1}

까지

Δ u_{n + 1} < 0.000001

u_{1} = - 0.34041 \dots : Δ u_{1} = 0.65958 \dots

f (u_{0}) = - 4 (- 1)^{2} - 7.26637 \dots (- 1) - 3.75025 \dots = - 0.48388 \dots

f^{^{'}} (u_{0}) = - 8 (- 1) - 7.26637 \dots = 0.73362 \dots

u_{1} = - 0.34041 \dots

Δ u_{1} = ∣ - 0.34041 \dots - (- 1) ∣ = 0.65958 \dots

Δ u_{1} = 0.65958 \dots

u_{2} = - 0.72346 \dots : Δ u_{2} = 0.38304 \dots

f (u_{1}) = - 4 (- 0.34041 \dots)^{2} - 7.26637 \dots (- 0.34041 \dots) - 3.75025 \dots = - 1.74019 \dots

f^{^{'}} (u_{1}) = - 8 (- 0.34041 \dots) - 7.26637 \dots = - 4.54302 \dots

u_{2} = - 0.72346 \dots

Δ u_{2} = ∣ - 0.72346 \dots - (- 0.34041 \dots) ∣ = 0.38304 \dots

Δ u_{2} = 0.38304 \dots

u_{3} = - 1.12038 \dots : Δ u_{3} = 0.39691 \dots

f (u_{2}) = - 4 (- 0.72346 \dots)^{2} - 7.26637 \dots (- 0.72346 \dots) - 3.75025 \dots = - 0.58690 \dots

f^{^{'}} (u_{2}) = - 8 (- 0.72346 \dots) - 7.26637 \dots = - 1.47865 \dots

u_{3} = - 1.12038 \dots

Δ u_{3} = ∣ - 1.12038 \dots - (- 0.72346 \dots) ∣ = 0.39691 \dots

Δ u_{3} = 0.39691 \dots

u_{4} = - 0.74896 \dots : Δ u_{4} = 0.37141 \dots

f (u_{3}) = - 4 (- 1.12038 \dots)^{2} - 7.26637 \dots (- 1.12038 \dots) - 3.75025 \dots = - 0.63017 \dots

f^{^{'}} (u_{3}) = - 8 (- 1.12038 \dots) - 7.26637 \dots = 1.69668 \dots

u_{4} = - 0.74896 \dots

Δ u_{4} = ∣ - 0.74896 \dots - (- 1.12038 \dots) ∣ = 0.37141 \dots

Δ u_{4} = 0.37141 \dots

u_{5} = - 1.18187 \dots : Δ u_{5} = 0.43290 \dots

f (u_{4}) = - 4 (- 0.74896 \dots)^{2} - 7.26637 \dots (- 0.74896 \dots) - 3.75025 \dots = - 0.55179 \dots

f^{^{'}} (u_{4}) = - 8 (- 0.74896 \dots) - 7.26637 \dots = - 1.27462 \dots

u_{5} = - 1.18187 \dots

Δ u_{5} = ∣ - 1.18187 \dots - (- 0.74896 \dots) ∣ = 0.43290 \dots

Δ u_{5} = 0.43290 \dots

u_{6} = - 0.83936 \dots : Δ u_{6} = 0.34251 \dots

f (u_{5}) = - 4 (- 1.18187 \dots)^{2} - 7.26637 \dots (- 1.18187 \dots) - 3.75025 \dots = - 0.74962 \dots

f^{^{'}} (u_{5}) = - 8 (- 1.18187 \dots) - 7.26637 \dots = 2.18860 \dots

u_{6} = - 0.83936 \dots

Δ u_{6} = ∣ - 0.83936 \dots - (- 1.18187 \dots) ∣ = 0.34251 \dots

Δ u_{6} = 0.34251 \dots

u_{7} = - 1.69025 \dots : Δ u_{7} = 0.85089 \dots

f (u_{6}) = - 4 (- 0.83936 \dots)^{2} - 7.26637 \dots (- 0.83936 \dots) - 3.75025 \dots = - 0.46925 \dots

f^{^{'}} (u_{6}) = - 8 (- 0.83936 \dots) - 7.26637 \dots = - 0.55149 \dots

u_{7} = - 1.69025 \dots

Δ u_{7} = ∣ - 1.69025 \dots - (- 0.83936 \dots) ∣ = 0.85089 \dots

Δ u_{7} = 0.85089 \dots

u_{8} = - 1.22729 \dots : Δ u_{8} = 0.46295 \dots

f (u_{7}) = - 4 (- 1.69025 \dots)^{2} - 7.26637 \dots (- 1.69025 \dots) - 3.75025 \dots = - 2.89606 \dots

f^{^{'}} (u_{7}) = - 8 (- 1.69025 \dots) - 7.26637 \dots = 6.25564 \dots

u_{8} = - 1.22729 \dots

Δ u_{8} = ∣ - 1.22729 \dots - (- 1.69025 \dots) ∣ = 0.46295 \dots

Δ u_{8} = 0.46295 \dots

u_{9} = - 0.89136 \dots : Δ u_{9} = 0.33593 \dots

f (u_{8}) = - 4 (- 1.22729 \dots)^{2} - 7.26637 \dots (- 1.22729 \dots) - 3.75025 \dots = - 0.85730 \dots

f^{^{'}} (u_{8}) = - 8 (- 1.22729 \dots) - 7.26637 \dots = 2.55202 \dots

u_{9} = - 0.89136 \dots

Δ u_{9} = ∣ - 0.89136 \dots - (- 1.22729 \dots) ∣ = 0.33593 \dots

Δ u_{9} = 0.33593 \dots

u_{10} = - 4.22467 \dots : Δ u_{10} = 3.33330 \dots

f (u_{9}) = - 4 (- 0.89136 \dots)^{2} - 7.26637 \dots (- 0.89136 \dots) - 3.75025 \dots = - 0.45139 \dots

f^{^{'}} (u_{9}) = - 8 (- 0.89136 \dots) - 7.26637 \dots = - 0.13541 \dots

u_{10} = - 4.22467 \dots

Δ u_{10} = ∣ - 4.22467 \dots - (- 0.89136 \dots) ∣ = 3.33330 \dots

Δ u_{10} = 3.33330 \dots

해결 방법을 찾을 수 없습니다

해결책은

u \approx 1.06659 \dots

뒤로 대체

u = sin (x)

sin (x) \approx 1.06659 \dots

sin (x) \approx 1.06659 \dots

sin (x) = 1.06659 \dots :

해결책 없음

sin (x) = 1.06659 \dots

- 1 \leq sin (x) \leq 1

해결책 없음

모든 솔루션 결합

해결책 없음

4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )} - 4 sin (x) = 0 :

해결책 없음

4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )} - 4 sin (x) = 0

4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )} - 4 sin (x)

단순화하세요:

\frac{4 cos ^{2} ( x ) + sin ^{2} ( x ) - 4 cos ^{2} ( x ) sin ( x )}{cos ^{2} ( x )}

4 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )} - 4 sin (x)

요소를 분수로 변환:

4 = \frac{4 cos ^{2} ( x )}{cos ^{2} ( x )}, 4 sin (x) = \frac{4 sin ( x ) cos ^{2} ( x )}{cos ^{2} ( x )}

= \frac{4 cos ^{2} ( x )}{cos ^{2} ( x )} + \frac{sin ^{2} ( x )}{cos ^{2} ( x )} - \frac{4 sin ( x ) cos ^{2} ( x )}{cos ^{2} ( x )}

분모가 같기 때문에, 분수를 합친다:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{4 cos ^{2} ( x ) + sin ^{2} ( x ) - 4 sin ( x ) cos ^{2} ( x )}{cos ^{2} ( x )}

\frac{4 cos ^{2} ( x ) + sin ^{2} ( x ) - 4 cos ^{2} ( x ) sin ( x )}{cos ^{2} ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

4 cos^{2} (x) + sin^{2} (x) - 4 cos^{2} (x) sin (x) = 0

삼각성을 사용하여 다시 쓰기

sin^{2} (x) + 4 cos^{2} (x) - 4 cos^{2} (x) sin (x)

피타고라스 정체성 사용:

cos^{2} (x) + sin^{2} (x) = 1

cos^{2} (x) = 1 - sin^{2} (x)

= sin^{2} (x) + 4 (1 - sin^{2} (x)) - 4 (1 - sin^{2} (x)) sin (x)

sin^{2} (x) + 4 (1 - sin^{2} (x)) - 4 (1 - sin^{2} (x)) sin (x)

간소화하다 :

- 3 sin^{2} (x) - 4 sin (x) + 4 sin^{3} (x) + 4

sin^{2} (x) + 4 (1 - sin^{2} (x)) - 4 (1 - sin^{2} (x)) sin (x)

= sin^{2} (x) + 4 (1 - sin^{2} (x)) - 4 sin (x) (1 - sin^{2} (x))

4 (1 - sin^{2} (x))

확대한다:

4 - 4 sin^{2} (x)

4 (1 - sin^{2} (x))

분배 법칙 적용:

a (b - c) = ab - a c

a = 4, b = 1, c = sin^{2} (x)

= 4 \cdot 1 - 4 sin^{2} (x)

숫자를 곱하시오:

4 \cdot 1 = 4

= 4 - 4 sin^{2} (x)

= sin^{2} (x) + 4 - 4 sin^{2} (x) - 4 (1 - sin^{2} (x)) sin (x)

- 4 sin (x) (1 - sin^{2} (x))

확대한다:

- 4 sin (x) + 4 sin^{3} (x)

- 4 sin (x) (1 - sin^{2} (x))

분배 법칙 적용:

a (b - c) = ab - a c

a = - 4 sin (x), b = 1, c = sin^{2} (x)

= - 4 sin (x) \cdot 1 - (- 4 sin (x)) sin^{2} (x)

마이너스 플러스 규칙 적용

- (- a) = a

= - 4 \cdot 1 \cdot sin (x) + 4 sin^{2} (x) sin (x)

- 4 \cdot 1 \cdot sin (x) + 4 sin^{2} (x) sin (x)

단순화하세요:

- 4 sin (x) + 4 sin^{3} (x)

- 4 \cdot 1 \cdot sin (x) + 4 sin^{2} (x) sin (x)

4 \cdot 1 \cdot sin (x) = 4 sin (x)

4 \cdot 1 \cdot sin (x)

숫자를 곱하시오:

4 \cdot 1 = 4

= 4 sin (x)

4 sin^{2} (x) sin (x) = 4 sin^{3} (x)

4 sin^{2} (x) sin (x)

지수 규칙 적용:

a^{b} \cdot a^{c} = a^{b + c}

sin^{2} (x) sin (x) = sin^{2 + 1} (x)

= 4 sin^{2 + 1} (x)

숫자 추가:

2 + 1 = 3

= 4 sin^{3} (x)

= - 4 sin (x) + 4 sin^{3} (x)

= - 4 sin (x) + 4 sin^{3} (x)

= sin^{2} (x) + 4 - 4 sin^{2} (x) - 4 sin (x) + 4 sin^{3} (x)

sin^{2} (x) + 4 - 4 sin^{2} (x) - 4 sin (x) + 4 sin^{3} (x)

단순화하세요:

- 3 sin^{2} (x) - 4 sin (x) + 4 sin^{3} (x) + 4

sin^{2} (x) + 4 - 4 sin^{2} (x) - 4 sin (x) + 4 sin^{3} (x)

집단적 용어

= sin^{2} (x) - 4 sin^{2} (x) - 4 sin (x) + 4 sin^{3} (x) + 4

유사 요소 추가:

sin^{2} (x) - 4 sin^{2} (x) = - 3 sin^{2} (x)

= - 3 sin^{2} (x) - 4 sin (x) + 4 sin^{3} (x) + 4

= - 3 sin^{2} (x) - 4 sin (x) + 4 sin^{3} (x) + 4

= - 3 sin^{2} (x) - 4 sin (x) + 4 sin^{3} (x) + 4

4 - 3 sin^{2} (x) - 4 sin (x) + 4 sin^{3} (x) = 0

대체로 해결

4 - 3 sin^{2} (x) - 4 sin (x) + 4 sin^{3} (x) = 0

하게:

sin (x) = u

4 - 3 u^{2} - 4 u + 4 u^{3} = 0

4 - 3 u^{2} - 4 u + 4 u^{3} = 0 : u \approx - 1.06659 \dots

4 - 3 u^{2} - 4 u + 4 u^{3} = 0

표준 양식으로 작성

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

4 u^{3} - 3 u^{2} - 4 u + 4 = 0

다음을 위한 하나의 솔루션 찾기

4 u^{3} - 3 u^{2} - 4 u + 4 = 0

뉴턴-랩슨을 이용하여:

u \approx - 1.06659 \dots

4 u^{3} - 3 u^{2} - 4 u + 4 = 0

뉴턴-랩슨 근사 정의

f (u) = 4 u^{3} - 3 u^{2} - 4 u + 4

f^{^{'}} (u)

찾다 :

12 u^{2} - 6 u - 4

\frac{d}{d u} (4 u^{3} - 3 u^{2} - 4 u + 4)

합계/차이 규칙 적용:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d u} (4 u^{3}) - \frac{d}{d u} (3 u^{2}) - \frac{d}{d u} (4 u) + \frac{d}{d u} (4)

\frac{d}{d u} (4 u^{3}) = 12 u^{2}

\frac{d}{d u} (4 u^{3})

정수를 빼라:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d u} (u^{3})

전원 규칙을 적용합니다:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 \cdot 3 u^{3 - 1}

단순화

= 12 u^{2}

\frac{d}{d u} (3 u^{2}) = 6 u

\frac{d}{d u} (3 u^{2})

정수를 빼라:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d u} (u^{2})

전원 규칙을 적용합니다:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 \cdot 2 u^{2 - 1}

단순화

= 6 u

\frac{d}{d u} (4 u) = 4

\frac{d}{d u} (4 u)

정수를 빼라:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d u}{d u}

공통 도함수 적용:

\frac{d u}{d u} = 1

= 4 \cdot 1

단순화

= 4

\frac{d}{d u} (4) = 0

\frac{d}{d u} (4)

상수의 도함수:

\frac{d}{d x} (a) = 0

= 0

= 12 u^{2} - 6 u - 4 + 0

단순화

= 12 u^{2} - 6 u - 4

렛

u_{0} = - 1

계산하다

u_{n + 1}

까지

Δ u_{n + 1} < 0.000001

u_{1} = - 1.07142 \dots : Δ u_{1} = 0.07142 \dots

f (u_{0}) = 4 (- 1)^{3} - 3 (- 1)^{2} - 4 (- 1) + 4 = 1

f^{^{'}} (u_{0}) = 12 (- 1)^{2} - 6 (- 1) - 4 = 14

u_{1} = - 1.07142 \dots

Δ u_{1} = ∣ - 1.07142 \dots - (- 1) ∣ = 0.07142 \dots

Δ u_{1} = 0.07142 \dots

u_{2} = - 1.06661 \dots : Δ u_{2} = 0.00481 \dots

f (u_{1}) = 4 (- 1.07142 \dots)^{3} - 3 (- 1.07142 \dots)^{2} - 4 (- 1.07142 \dots) + 4 = - 0.07798 \dots

f^{^{'}} (u_{1}) = 12 (- 1.07142 \dots)^{2} - 6 (- 1.07142 \dots) - 4 = 16.20408 \dots

u_{2} = - 1.06661 \dots

Δ u_{2} = ∣ - 1.06661 \dots - (- 1.07142 \dots) ∣ = 0.00481 \dots

Δ u_{2} = 0.00481 \dots

u_{3} = - 1.06659 \dots : Δ u_{3} = 0.00002 \dots

f (u_{2}) = 4 (- 1.06661 \dots)^{3} - 3 (- 1.06661 \dots)^{2} - 4 (- 1.06661 \dots) + 4 = - 0.00036 \dots

f^{^{'}} (u_{2}) = 12 (- 1.06661 \dots)^{2} - 6 (- 1.06661 \dots) - 4 = 16.05172 \dots

u_{3} = - 1.06659 \dots

Δ u_{3} = ∣ - 1.06659 \dots - (- 1.06661 \dots) ∣ = 0.00002 \dots

Δ u_{3} = 0.00002 \dots

u_{4} = - 1.06659 \dots : Δ u_{4} = 5.14172 E - 10

f (u_{3}) = 4 (- 1.06659 \dots)^{3} - 3 (- 1.06659 \dots)^{2} - 4 (- 1.06659 \dots) + 4 = - 8.25297 E - 9

f^{^{'}} (u_{3}) = 12 (- 1.06659 \dots)^{2} - 6 (- 1.06659 \dots) - 4 = 16.05100 \dots

u_{4} = - 1.06659 \dots

Δ u_{4} = ∣ - 1.06659 \dots - (- 1.06659 \dots) ∣ = 5.14172 E - 10

Δ u_{4} = 5.14172 E - 10

u \approx - 1.06659 \dots

긴 나눗셈 적용:

\frac{4 u ^{3} - 3 u ^{2} - 4 u + 4}{u + 1.06659 \dots} = 4 u^{2} - 7.26637 \dots u + 3.75025 \dots

4 u^{2} - 7.26637 \dots u + 3.75025 \dots \approx 0

다음을 위한 하나의 솔루션 찾기

4 u^{2} - 7.26637 \dots u + 3.75025 \dots = 0

뉴턴-랩슨을 이용하여:

솔루션 없음

u \in R

4 u^{2} - 7.26637 \dots u + 3.75025 \dots = 0

뉴턴-랩슨 근사 정의

f (u) = 4 u^{2} - 7.26637 \dots u + 3.75025 \dots

f^{^{'}} (u)

찾다 :

8 u - 7.26637 \dots

\frac{d}{d u} (4 u^{2} - 7.26637 \dots u + 3.75025 \dots)

합계/차이 규칙 적용:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d u} (4 u^{2}) - \frac{d}{d u} (7.26637 \dots u) + \frac{d}{d u} (3.75025 \dots)

\frac{d}{d u} (4 u^{2}) = 8 u

\frac{d}{d u} (4 u^{2})

정수를 빼라:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d u} (u^{2})

전원 규칙을 적용합니다:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 \cdot 2 u^{2 - 1}

단순화

= 8 u

\frac{d}{d u} (7.26637 \dots u) = 7.26637 \dots

\frac{d}{d u} (7.26637 \dots u)

정수를 빼라:

(a \cdot f)^{'} = a \cdot f^{'}

= 7.26637 \dots \frac{d u}{d u}

공통 도함수 적용:

\frac{d u}{d u} = 1

= 7.26637 \dots \cdot 1

단순화

= 7.26637 \dots

\frac{d}{d u} (3.75025 \dots) = 0

\frac{d}{d u} (3.75025 \dots)

상수의 도함수:

\frac{d}{d x} (a) = 0

= 0

= 8 u - 7.26637 \dots + 0

단순화

= 8 u - 7.26637 \dots

렛

u_{0} = 1

계산하다

u_{n + 1}

까지

Δ u_{n + 1} < 0.000001

u_{1} = 0.34041 \dots : Δ u_{1} = 0.65958 \dots

f (u_{0}) = 4 \cdot 1^{2} - 7.26637 \dots \cdot 1 + 3.75025 \dots = 0.48388 \dots

f^{^{'}} (u_{0}) = 8 \cdot 1 - 7.26637 \dots = 0.73362 \dots

u_{1} = 0.34041 \dots

Δ u_{1} = ∣ 0.34041 \dots - 1 ∣ = 0.65958 \dots

Δ u_{1} = 0.65958 \dots

u_{2} = 0.72346 \dots : Δ u_{2} = 0.38304 \dots

f (u_{1}) = 4 \cdot 0.34041 \dots^{2} - 7.26637 \dots \cdot 0.34041 \dots + 3.75025 \dots = 1.74019 \dots

f^{^{'}} (u_{1}) = 8 \cdot 0.34041 \dots - 7.26637 \dots = - 4.54302 \dots

u_{2} = 0.72346 \dots

Δ u_{2} = ∣ 0.72346 \dots - 0.34041 \dots ∣ = 0.38304 \dots

Δ u_{2} = 0.38304 \dots

u_{3} = 1.12038 \dots : Δ u_{3} = 0.39691 \dots

f (u_{2}) = 4 \cdot 0.72346 \dots^{2} - 7.26637 \dots \cdot 0.72346 \dots + 3.75025 \dots = 0.58690 \dots

f^{^{'}} (u_{2}) = 8 \cdot 0.72346 \dots - 7.26637 \dots = - 1.47865 \dots

u_{3} = 1.12038 \dots

Δ u_{3} = ∣ 1.12038 \dots - 0.72346 \dots ∣ = 0.39691 \dots

Δ u_{3} = 0.39691 \dots

u_{4} = 0.74896 \dots : Δ u_{4} = 0.37141 \dots

f (u_{3}) = 4 \cdot 1.12038 \dots^{2} - 7.26637 \dots \cdot 1.12038 \dots + 3.75025 \dots = 0.63017 \dots

f^{^{'}} (u_{3}) = 8 \cdot 1.12038 \dots - 7.26637 \dots = 1.69668 \dots

u_{4} = 0.74896 \dots

Δ u_{4} = ∣ 0.74896 \dots - 1.12038 \dots ∣ = 0.37141 \dots

Δ u_{4} = 0.37141 \dots

u_{5} = 1.18187 \dots : Δ u_{5} = 0.43290 \dots

f (u_{4}) = 4 \cdot 0.74896 \dots^{2} - 7.26637 \dots \cdot 0.74896 \dots + 3.75025 \dots = 0.55179 \dots

f^{^{'}} (u_{4}) = 8 \cdot 0.74896 \dots - 7.26637 \dots = - 1.27462 \dots

u_{5} = 1.18187 \dots

Δ u_{5} = ∣ 1.18187 \dots - 0.74896 \dots ∣ = 0.43290 \dots

Δ u_{5} = 0.43290 \dots

u_{6} = 0.83936 \dots : Δ u_{6} = 0.34251 \dots

f (u_{5}) = 4 \cdot 1.18187 \dots^{2} - 7.26637 \dots \cdot 1.18187 \dots + 3.75025 \dots = 0.74962 \dots

f^{^{'}} (u_{5}) = 8 \cdot 1.18187 \dots - 7.26637 \dots = 2.18860 \dots

u_{6} = 0.83936 \dots

Δ u_{6} = ∣ 0.83936 \dots - 1.18187 \dots ∣ = 0.34251 \dots

Δ u_{6} = 0.34251 \dots

u_{7} = 1.69025 \dots : Δ u_{7} = 0.85089 \dots

f (u_{6}) = 4 \cdot 0.83936 \dots^{2} - 7.26637 \dots \cdot 0.83936 \dots + 3.75025 \dots = 0.46925 \dots

f^{^{'}} (u_{6}) = 8 \cdot 0.83936 \dots - 7.26637 \dots = - 0.55149 \dots

u_{7} = 1.69025 \dots

Δ u_{7} = ∣ 1.69025 \dots - 0.83936 \dots ∣ = 0.85089 \dots

Δ u_{7} = 0.85089 \dots

u_{8} = 1.22729 \dots : Δ u_{8} = 0.46295 \dots

f (u_{7}) = 4 \cdot 1.69025 \dots^{2} - 7.26637 \dots \cdot 1.69025 \dots + 3.75025 \dots = 2.89606 \dots

f^{^{'}} (u_{7}) = 8 \cdot 1.69025 \dots - 7.26637 \dots = 6.25564 \dots

u_{8} = 1.22729 \dots

Δ u_{8} = ∣ 1.22729 \dots - 1.69025 \dots ∣ = 0.46295 \dots

Δ u_{8} = 0.46295 \dots

u_{9} = 0.89136 \dots : Δ u_{9} = 0.33593 \dots

f (u_{8}) = 4 \cdot 1.22729 \dots^{2} - 7.26637 \dots \cdot 1.22729 \dots + 3.75025 \dots = 0.85730 \dots

f^{^{'}} (u_{8}) = 8 \cdot 1.22729 \dots - 7.26637 \dots = 2.55202 \dots

u_{9} = 0.89136 \dots

Δ u_{9} = ∣ 0.89136 \dots - 1.22729 \dots ∣ = 0.33593 \dots

Δ u_{9} = 0.33593 \dots

u_{10} = 4.22467 \dots : Δ u_{10} = 3.33330 \dots

f (u_{9}) = 4 \cdot 0.89136 \dots^{2} - 7.26637 \dots \cdot 0.89136 \dots + 3.75025 \dots = 0.45139 \dots

f^{^{'}} (u_{9}) = 8 \cdot 0.89136 \dots - 7.26637 \dots = - 0.13541 \dots

u_{10} = 4.22467 \dots

Δ u_{10} = ∣ 4.22467 \dots - 0.89136 \dots ∣ = 3.33330 \dots

Δ u_{10} = 3.33330 \dots

해결 방법을 찾을 수 없습니다

해결책은

u \approx - 1.06659 \dots

뒤로 대체

u = sin (x)

sin (x) \approx - 1.06659 \dots

sin (x) \approx - 1.06659 \dots

sin (x) = - 1.06659 \dots :

해결책 없음

sin (x) = - 1.06659 \dots

- 1 \leq sin (x) \leq 1

해결책 없음

모든 솔루션 결합

해결책 없음

모든 솔루션 결합

해결책 없음

해법을 원래 방정식에 연결하여 검증

솔루션을 에 연결하여 확인합니다

tan^{2} (x) - 4 sin (x) + 4 = 0

방정식에 맞지 않는 것은 제거하십시오.

솔루션 없음 x \in R

그래프

인기 있는 예

1 - cos (2 x) = 0

sin (x) = \frac{37}{64}

15cos^2(x)+7cos(x)-2=0

15 cos^{2} (x) + 7 cos (x) - 2 = 0

2(sin(t))^2-sin(t)-1=0

2 (sin (t))^{2} - sin (t) - 1 = 0

cos (x) = 0.625