sin^2(x)cos^2(x)=(2-sqrt(2))/(16)

Solución

sin^{2} (x) cos^{2} (x) = \frac{2 - 2}{16}

x = 0.19634 \dots + 2 πn, x = π - 0.19634 \dots + 2 πn, x = - 0.19634 \dots + 2 πn, x = π + 0.19634 \dots + 2 πn, x = 1.37444 \dots + 2 πn, x = π - 1.37444 \dots + 2 πn, x = - 1.37444 \dots + 2 πn, x = π + 1.37444 \dots + 2 πn

Pasos de solución

sin^{2} (x) cos^{2} (x) = \frac{2 - 2}{16}

Restar

\frac{2 - 2}{16}

de ambos lados

sin^{2} (x) cos^{2} (x) - \frac{2 - 1}{8 2} = 0

Simplificar

sin^{2} (x) cos^{2} (x) - \frac{2 - 1}{8 2} : \frac{8 2 sin ^{2} ( x ) cos ^{2} ( x ) - 2 + 1}{8 2}

\frac{8 2 sin ^{2} ( x ) cos ^{2} ( x ) - 2 + 1}{8 2} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

82 sin^{2} (x) cos^{2} (x) - 2 + 1 = 0

Re-escribir usando identidades trigonométricas

1 - 2 + (1 - sin^{2} (x)) \cdot 8 sin^{2} (x) 2 = 0

Usando el método de sustitución

sin (x) = \frac{2 - 2 64 + 32 2 + 16}{8}, sin (x) = - \frac{2 - 2 64 + 32 2 + 16}{8}, sin (x) = \frac{2 2 64 + 32 2 + 16}{8}, sin (x) = - \frac{2 2 64 + 32 2 + 16}{8}

sin (x) = \frac{2 - 2 64 + 32 2 + 16}{8} : x = arcsin \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn, x = π - arcsin \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn

sin (x) = - \frac{2 - 2 64 + 32 2 + 16}{8} : x = arcsin - \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn, x = π + arcsin \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn

sin (x) = \frac{2 2 64 + 32 2 + 16}{8} : x = arcsin \frac{2 2 64 + 32 2 + 16}{8} + 2 πn, x = π - arcsin \frac{2 2 64 + 32 2 + 16}{8} + 2 πn

sin (x) = - \frac{2 2 64 + 32 2 + 16}{8} : x = arcsin - \frac{2 2 64 + 32 2 + 16}{8} + 2 πn, x = π + arcsin \frac{2 2 64 + 32 2 + 16}{8} + 2 πn

Combinar toda las soluciones

x = arcsin \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn, x = π - arcsin \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn, x = arcsin - \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn, x = π + arcsin \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn, x = arcsin \frac{2 2 64 + 32 2 + 16}{8} + 2 πn, x = π - arcsin \frac{2 2 64 + 32 2 + 16}{8} + 2 πn, x = arcsin - \frac{2 2 64 + 32 2 + 16}{8} + 2 πn, x = π + arcsin \frac{2 2 64 + 32 2 + 16}{8} + 2 πn

Mostrar soluciones en forma decimal

x = 0.19634 \dots + 2 πn, x = π - 0.19634 \dots + 2 πn, x = - 0.19634 \dots + 2 πn, x = π + 0.19634 \dots + 2 πn, x = 1.37444 \dots + 2 πn, x = π - 1.37444 \dots + 2 πn, x = - 1.37444 \dots + 2 πn, x = π + 1.37444 \dots + 2 πn

(sin (x) - 1) (sin (x) - 5) = 0

(4 sin^{2} (x) - 1) (cos^{2} (x) - 1) = 0

3 sin^{2} (x) - 6 sin (x) = - 3, 0 \leq x \leq 2 π

1 + sin (π \cdot t) = \frac{3}{2}

- cos (x) = sin^{2} (x) - 1