English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

|sin(x)|= 2/pi

Solución

∣ sin (x) ∣ = \frac{2}{π}

x = - 0.69010 \dots + 2 πn, x = π + 0.69010 \dots + 2 πn, x = 0.69010 \dots + 2 πn, x = π - 0.69010 \dots + 2 πn

Grados

x = - 39.54022 \dots^{\circ} + 36 0^{\circ} n, x = 219.54022 \dots^{\circ} + 36 0^{\circ} n, x = 39.54022 \dots^{\circ} + 36 0^{\circ} n, x = 140.45977 \dots^{\circ} + 36 0^{\circ} n

Pasos de solución

∣ sin (x) ∣ = \frac{2}{π}

Usando el método de sustitución

∣ sin (x) ∣ = \frac{2}{π}

Sea:

sin (x) = u

∣ u ∣ = \frac{2}{π}

∣ u ∣ = \frac{2}{π} : u = - \frac{2}{π} or u = \frac{2}{π}

∣ u ∣ = \frac{2}{π}

Aplicar las propiedades de los valores absolutos: Pi

∣ u ∣ = a, a > 0

entonces

u = a

u = - a

u = - \frac{2}{π} or u = \frac{2}{π}

Sustituir en la ecuación

u = sin (x)

sin (x) = - \frac{2}{π} or sin (x) = \frac{2}{π}

sin (x) = - \frac{2}{π} or sin (x) = \frac{2}{π}

sin (x) = - \frac{2}{π} : x = arcsin (- \frac{2}{π}) + 2 πn, x = π + arcsin (\frac{2}{π}) + 2 πn

sin (x) = - \frac{2}{π}

Aplicar propiedades trigonométricas inversas

sin (x) = - \frac{2}{π}

Soluciones generales para

sin (x) = - \frac{2}{π}

sin (x) = - a \Rightarrow x = arcsin (- a) + 2 πn, x = π + arcsin (a) + 2 πn

x = arcsin (- \frac{2}{π}) + 2 πn, x = π + arcsin (\frac{2}{π}) + 2 πn

x = arcsin (- \frac{2}{π}) + 2 πn, x = π + arcsin (\frac{2}{π}) + 2 πn

sin (x) = \frac{2}{π} : x = arcsin (\frac{2}{π}) + 2 πn, x = π - arcsin (\frac{2}{π}) + 2 πn

sin (x) = \frac{2}{π}

Aplicar propiedades trigonométricas inversas

sin (x) = \frac{2}{π}

Soluciones generales para

sin (x) = \frac{2}{π}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

x = arcsin (\frac{2}{π}) + 2 πn, x = π - arcsin (\frac{2}{π}) + 2 πn

x = arcsin (\frac{2}{π}) + 2 πn, x = π - arcsin (\frac{2}{π}) + 2 πn

Combinar toda las soluciones

x = arcsin (- \frac{2}{π}) + 2 πn, x = π + arcsin (\frac{2}{π}) + 2 πn, x = arcsin (\frac{2}{π}) + 2 πn, x = π - arcsin (\frac{2}{π}) + 2 πn

Mostrar soluciones en forma decimal

x = - 0.69010 \dots + 2 πn, x = π + 0.69010 \dots + 2 πn, x = 0.69010 \dots + 2 πn, x = π - 0.69010 \dots + 2 πn

2 + cos (2 θ) = 0

cos (\frac{π ( x + 5 )}{3}) = \frac{1}{2}

(sin (x))^{2} + (1 - 2) sin (x) - 2 = 0

4 sin^{2} (A) - 1 = 0

tan (θ) = \frac{22}{7}