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-(1/2)^2+cos(θ^2)=1

Solución

- (\frac{1}{2})^{2} + cos (θ^{2}) = 1

Solución

Sin soluci \overset{o}{ˊ} n para θ \in R

Pasos de solución

- (\frac{1}{2})^{2} + cos (θ^{2}) = 1

Simplificar

- (\frac{1}{2})^{2} + cos (θ^{2}) : - \frac{1}{4} + cos (θ^{2})

- (\frac{1}{2})^{2} + cos (θ^{2})

(\frac{1}{2})^{2} = \frac{1}{2 ^{2}}

(\frac{1}{2})^{2}

Aplicar las leyes de los exponentes:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{2 ^{2}}

Aplicar la regla

1^{a} = 1

1^{2} = 1

= \frac{1}{2 ^{2}}

= - \frac{1}{2 ^{2}} + cos (θ^{2})

2^{2} = 4

= - \frac{1}{4} + cos (θ^{2})

- \frac{1}{4} + cos (θ^{2}) = 1

Mover

\frac{1}{4}

al lado derecho

- \frac{1}{4} + cos (θ^{2}) = 1

Sumar

\frac{1}{4}

a ambos lados

- \frac{1}{4} + cos (θ^{2}) + \frac{1}{4} = 1 + \frac{1}{4}

Simplificar

- \frac{1}{4} + cos (θ^{2}) + \frac{1}{4} = 1 + \frac{1}{4}

Simplificar

- \frac{1}{4} + cos (θ^{2}) + \frac{1}{4} : cos (θ^{2})

- \frac{1}{4} + cos (θ^{2}) + \frac{1}{4}

Sumar elementos similares:

- \frac{1}{4} + \frac{1}{4} = 0

= cos (θ^{2})

Simplificar

1 + \frac{1}{4} : \frac{5}{4}

1 + \frac{1}{4}

Convertir a fracción:

1 = \frac{1 \cdot 4}{4}

= \frac{1 \cdot 4}{4} + \frac{1}{4}

Ya que los denominadores son iguales, combinar las fracciones:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 4 + 1}{4}

1 \cdot 4 + 1 = 5

1 \cdot 4 + 1

Multiplicar los numeros:

1 \cdot 4 = 4

= 4 + 1

Sumar:

4 + 1 = 5

= 5

= \frac{5}{4}

cos (θ^{2}) = \frac{5}{4}

cos (θ^{2}) = \frac{5}{4}

cos (θ^{2}) = \frac{5}{4}

- 1 \leq cos (x) \leq 1

Sin soluci \overset{o}{ˊ} n para θ \in R

Ejemplos populares

0 = 2 cos (2 θ)

2sec^2(x)+tan(x)=8

2 sec^{2} (x) + tan (x) = 8

tan(θ)=(sqrt(48))/8

tan (θ) = \frac{48}{8}

-2cos(2x)=2sin(x)

- 2 cos (2 x) = 2 sin (x)

sin(θ)-0.2cos(θ)=(7.51)/(9.8)

sin (θ) - 0.2 cos (θ) = \frac{7.51}{9.8}