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人気のある三角関数 >

(cot^2(x))/(1+sin(x))=(csc(x)-1)/(sin^2(x))

解

\frac{cot ^{2} ( x )}{1 + sin ( x )} = \frac{csc ( x ) - 1}{sin ^{2} ( x )}

解

x = \frac{π}{2} + 2 πn

+1

度

x = 9 0^{\circ} + 36 0^{\circ} n

解答ステップ

\frac{cot ^{2} ( x )}{1 + sin ( x )} = \frac{csc ( x ) - 1}{sin ^{2} ( x )}

両辺から

\frac{csc ( x ) - 1}{sin ^{2} ( x )}

を引く

\frac{cot ^{2} ( x )}{1 + sin ( x )} - \frac{csc ( x ) - 1}{sin ^{2} ( x )} = 0

簡素化

\frac{cot ^{2} ( x )}{1 + sin ( x )} - \frac{csc ( x ) - 1}{sin ^{2} ( x )} : \frac{cot ^{2} ( x ) sin ^{2} ( x ) - ( csc ( x ) - 1 ) ( sin ( x ) + 1 )}{sin ^{2} ( x ) ( sin ( x ) + 1 )}

\frac{cot ^{2} ( x )}{1 + sin ( x )} - \frac{csc ( x ) - 1}{sin ^{2} ( x )}

以下の最小公倍数:

1 + sin (x), sin^{2} (x) : sin^{2} (x) (sin (x) + 1)

1 + sin (x), sin^{2} (x)

最小公倍数 (LCM)

1 + sin (x)

または以下のいずれかに現れる因数で構成された式を計算する:

sin^{2} (x)

= sin^{2} (x) (sin (x) + 1)

LCMに基づいて分数を調整する

該当する分母を乗じてLCMに変えるために

必要な量で各分子を乗じる

sin^{2} (x) (sin (x) + 1)

\frac{cot ^{2} ( x )}{1 + sin ( x )}

の場合

:

分母と分子に以下を乗じる:

sin^{2} (x)

\frac{cot ^{2} ( x )}{1 + sin ( x )} = \frac{cot ^{2} ( x ) sin ^{2} ( x )}{( 1 + sin ( x ) ) sin ^{2} ( x )}

\frac{csc ( x ) - 1}{sin ^{2} ( x )}

の場合

:

分母と分子に以下を乗じる:

sin (x) + 1

\frac{csc ( x ) - 1}{sin ^{2} ( x )} = \frac{( csc ( x ) - 1 ) ( sin ( x ) + 1 )}{sin ^{2} ( x ) ( sin ( x ) + 1 )}

= \frac{cot ^{2} ( x ) sin ^{2} ( x )}{( 1 + sin ( x ) ) sin ^{2} ( x )} - \frac{( csc ( x ) - 1 ) ( sin ( x ) + 1 )}{sin ^{2} ( x ) ( sin ( x ) + 1 )}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{cot ^{2} ( x ) sin ^{2} ( x ) - ( csc ( x ) - 1 ) ( sin ( x ) + 1 )}{sin ^{2} ( x ) ( sin ( x ) + 1 )}

\frac{cot ^{2} ( x ) sin ^{2} ( x ) - ( csc ( x ) - 1 ) ( sin ( x ) + 1 )}{sin ^{2} ( x ) ( sin ( x ) + 1 )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

cot^{2} (x) sin^{2} (x) - (csc (x) - 1) (sin (x) + 1) = 0

三角関数の公式を使用して書き換える

- (- 1 + csc (x)) (1 + sin (x)) + cot^{2} (x) sin^{2} (x)

ピタゴラスの公式を使用する:

1 + cot^{2} (x) = csc^{2} (x)

cot^{2} (x) = csc^{2} (x) - 1

= - (- 1 + csc (x)) (1 + sin (x)) + (csc^{2} (x) - 1) sin^{2} (x)

- (- 1 + csc (x)) (1 + sin (x)) + (- 1 + csc^{2} (x)) sin^{2} (x) = 0

因数

- (- 1 + csc (x)) (1 + sin (x)) + (- 1 + csc^{2} (x)) sin^{2} (x) : (- 1 + csc (x)) (- 1 - sin (x) + sin^{2} (x) + sin^{2} (x) csc (x))

- (- 1 + csc (x)) (1 + sin (x)) + (- 1 + csc^{2} (x)) sin^{2} (x)

因数

- 1 + csc^{2} (x) : (csc (x) + 1) (csc (x) - 1)

- 1 + csc^{2} (x)

1

を書き換え

1^{2}

= csc^{2} (x) - 1^{2}

2乗の差の公式を適用する:

x^{2} - y^{2} = (x + y) (x - y)

csc^{2} (x) - 1^{2} = (csc (x) + 1) (csc (x) - 1)

= (csc (x) + 1) (csc (x) - 1)

= - (csc (x) - 1) (sin (x) + 1) + sin^{2} (x) (csc (x) + 1) (csc (x) - 1)

共通項をくくり出す

(- 1 + csc (x))

= (- 1 + csc (x)) (- (1 + sin (x)) + (1 + csc (x)) sin^{2} (x))

拡張

sin^{2} (x) (csc (x) + 1) - (sin (x) + 1) : - 1 - sin (x) + sin^{2} (x) + sin^{2} (x) csc (x)

- (1 + sin (x)) + (1 + csc (x)) sin^{2} (x)

= - (1 + sin (x)) + sin^{2} (x) (1 + csc (x))

- (1 + sin (x)) : - 1 - sin (x)

- (1 + sin (x))

括弧を分配する

= - (1) - (sin (x))

マイナス・プラスの規則を適用する

+ (- a) = - a

= - 1 - sin (x)

= - 1 - sin (x) + (1 + csc (x)) sin^{2} (x)

拡張

sin^{2} (x) (1 + csc (x)) : sin^{2} (x) + sin^{2} (x) csc (x)

sin^{2} (x) (1 + csc (x))

分配法則を適用する:

a (b + c) = ab + a c

a = sin^{2} (x), b = 1, c = csc (x)

= sin^{2} (x) \cdot 1 + sin^{2} (x) csc (x)

= 1 \cdot sin^{2} (x) + sin^{2} (x) csc (x)

乗算:

1 \cdot sin^{2} (x) = sin^{2} (x)

= sin^{2} (x) + sin^{2} (x) csc (x)

= - 1 - sin (x) + sin^{2} (x) + sin^{2} (x) csc (x)

= (csc (x) - 1) (sin^{2} (x) + sin^{2} (x) csc (x) - sin (x) - 1)

(- 1 + csc (x)) (- 1 - sin (x) + sin^{2} (x) + sin^{2} (x) csc (x)) = 0

各部分を別個に解く

- 1 + csc (x) = 0 or - 1 - sin (x) + sin^{2} (x) + sin^{2} (x) csc (x) = 0

- 1 + csc (x) = 0 : x = \frac{π}{2} + 2 πn

- 1 + csc (x) = 0

1

を右側に移動します

- 1 + csc (x) = 0

両辺に

1

を足す

- 1 + csc (x) + 1 = 0 + 1

簡素化

csc (x) = 1

csc (x) = 1

以下の一般解

csc (x) = 1

csc (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} csc (x) Undefiend 22 \frac{2 3}{3} 1 \frac{2 3}{3} 22 x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} csc (x) Undefiend - 2 - 2 - \frac{2 3}{3} - 1 - \frac{2 3}{3} - 2 - 2

x = \frac{π}{2} + 2 πn

x = \frac{π}{2} + 2 πn

- 1 - sin (x) + sin^{2} (x) + sin^{2} (x) csc (x) = 0 : x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

- 1 - sin (x) + sin^{2} (x) + sin^{2} (x) csc (x) = 0

三角関数の公式を使用して書き換える

- 1 - sin (x) + sin^{2} (x) + csc (x) sin^{2} (x)

基本的な三角関数の公式を使用する:

csc (x) = \frac{1}{sin ( x )}

= - 1 - sin (x) + sin^{2} (x) + \frac{1}{sin ( x )} sin^{2} (x)

簡素化

- 1 - sin (x) + sin^{2} (x) + \frac{1}{sin ( x )} sin^{2} (x) : sin^{2} (x) - 1

- 1 - sin (x) + sin^{2} (x) + \frac{1}{sin ( x )} sin^{2} (x)

\frac{1}{sin ( x )} sin^{2} (x) = sin (x)

\frac{1}{sin ( x )} sin^{2} (x)

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot sin ^{2} ( x )}{sin ( x )}

乗算:

1 \cdot sin^{2} (x) = sin^{2} (x)

= \frac{sin ^{2} ( x )}{sin ( x )}

共通因数を約分する:

sin (x)

= sin (x)

= - 1 - sin (x) + sin^{2} (x) + sin (x)

条件のようなグループ

= - sin (x) + sin^{2} (x) + sin (x) - 1

類似した元を足す:

- sin (x) + sin (x) = 0

= sin^{2} (x) - 1

= sin^{2} (x) - 1

- 1 + sin^{2} (x) = 0

置換で解く

- 1 + sin^{2} (x) = 0

仮定:

sin (x) = u

- 1 + u^{2} = 0

- 1 + u^{2} = 0 : u = 1, u = - 1

- 1 + u^{2} = 0

1

を右側に移動します

- 1 + u^{2} = 0

両辺に

1

を足す

- 1 + u^{2} + 1 = 0 + 1

簡素化

u^{2} = 1

u^{2} = 1

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

u = 1, u = - 1

1 = 1

1

規則を適用

1 = 1

= 1

- 1 = - 1

- 1

規則を適用

1 = 1

= - 1

u = 1, u = - 1

代用を戻す

u = sin (x)

sin (x) = 1, sin (x) = - 1

sin (x) = 1, sin (x) = - 1

sin (x) = 1 : x = \frac{π}{2} + 2 πn

sin (x) = 1

以下の一般解

sin (x) = 1

sin (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{2} + 2 πn

x = \frac{π}{2} + 2 πn

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

sin (x) = - 1

以下の一般解

sin (x) = - 1

sin (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{3 π}{2} + 2 πn

x = \frac{3 π}{2} + 2 πn

すべての解を組み合わせる

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

すべての解を組み合わせる

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

equationは以下で未定義のため:

\frac{3 π}{2} + 2 πn

x = \frac{π}{2} + 2 πn

グラフ

人気の例

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