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((1-(cos(x))^2))/((1+sin(x)))=sin(x)

Solución

\frac{( 1 - ( cos ( x ) ) ^{2} )}{( 1 + sin ( x ) )} = sin (x)

x = 2 πn, x = π + 2 πn

Grados

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

Pasos de solución

\frac{( 1 - ( cos ( x ) ) ^{2} )}{( 1 + sin ( x ) )} = sin (x)

Restar

sin (x)

de ambos lados

\frac{1 - cos ^{2} ( x )}{1 + sin ( x )} - sin (x) = 0

Simplificar

\frac{1 - cos ^{2} ( x )}{1 + sin ( x )} - sin (x) : \frac{1 - cos ^{2} ( x ) - sin ( x ) ( 1 + sin ( x ) )}{1 + sin ( x )}

\frac{1 - cos ^{2} ( x )}{1 + sin ( x )} - sin (x)

Convertir a fracción:

sin (x) = \frac{sin ( x ) ( 1 + sin ( x ) )}{1 + sin ( x )}

= \frac{1 - cos ^{2} ( x )}{1 + sin ( x )} - \frac{sin ( x ) ( 1 + sin ( x ) )}{1 + sin ( x )}

Ya que los denominadores son iguales, combinar las fracciones:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 - cos ^{2} ( x ) - sin ( x ) ( 1 + sin ( x ) )}{1 + sin ( x )}

\frac{1 - cos ^{2} ( x ) - sin ( x ) ( 1 + sin ( x ) )}{1 + sin ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

1 - cos^{2} (x) - sin (x) (1 + sin (x)) = 0

Re-escribir usando identidades trigonométricas

1 - cos^{2} (x) - (1 + sin (x)) sin (x)

Utilizar la identidad pitagórica:

1 = cos^{2} (x) + sin^{2} (x)

1 - cos^{2} (x) = sin^{2} (x)

= - sin (x) (1 + sin (x)) + sin^{2} (x)

Simplificar

- sin (x) (1 + sin (x)) + sin^{2} (x) : - sin (x)

- sin (x) (1 + sin (x)) + sin^{2} (x)

Expandir

- sin (x) (1 + sin (x)) : - sin (x) - sin^{2} (x)

- sin (x) (1 + sin (x))

Poner los parentesis utilizando:

a (b + c) = ab + a c

a = - sin (x), b = 1, c = sin (x)

= - sin (x) \cdot 1 + (- sin (x)) sin (x)

Aplicar las reglas de los signos

+ (- a) = - a

= - 1 \cdot sin (x) - sin (x) sin (x)

Simplificar

- 1 \cdot sin (x) - sin (x) sin (x) : - sin (x) - sin^{2} (x)

- 1 \cdot sin (x) - sin (x) sin (x)

1 \cdot sin (x) = sin (x)

1 \cdot sin (x)

Multiplicar:

1 \cdot sin (x) = sin (x)

= sin (x)

sin (x) sin (x) = sin^{2} (x)

sin (x) sin (x)

Aplicar las leyes de los exponentes:

a^{b} \cdot a^{c} = a^{b + c}

sin (x) sin (x) = sin^{1 + 1} (x)

= sin^{1 + 1} (x)

Sumar:

1 + 1 = 2

= sin^{2} (x)

= - sin (x) - sin^{2} (x)

= - sin (x) - sin^{2} (x)

= - sin (x) - sin^{2} (x) + sin^{2} (x)

Sumar elementos similares:

- sin^{2} (x) + sin^{2} (x) = 0

= - sin (x)

= - sin (x)

- sin (x) = 0

Dividir ambos lados entre

- 1

- sin (x) = 0

Dividir ambos lados entre

- 1

\frac{- sin ( x )}{- 1} = \frac{0}{- 1}

Simplificar

sin (x) = 0

sin (x) = 0

Soluciones generales para

sin (x) = 0

tabla de valores periódicos con

2 πn

intervalos:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Resolver

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

x, arctan (x) = 0

5 sin (x) = - 3

csc^{2} (x) = 2 \cdot cot^{2} (x)

3 sin (2 x) = cos (2 x)

3 \cdot 2 = \frac{50 sin ( x )}{9.8}