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sin(B)=(7sin(36))/(12)

Solución

sin (B) = \frac{7 sin ( 3 6 ^{\circ} )}{12}

Solución

B = 0.34997 \dots + 36 0^{\circ} n, B = 18 0^{\circ} - 0.34997 \dots + 36 0^{\circ} n

radianes

B = 0.34997 \dots + 2 πn, B = π - 0.34997 \dots + 2 πn

Pasos de solución

sin (B) = \frac{7 sin ( 3 6 ^{\circ} )}{12}

sin (3 6^{\circ}) = \frac{2 5 - 5}{4}

sin (3 6^{\circ})

Demostrar que:

cos (3 6^{\circ}) - sin (1 8^{\circ}) = \frac{1}{2}

Utilizar el siguiente producto para la identidad de suma de ángulos:

2 sin (x) cos (y) = sin (x + y) - sin (x - y)

2 cos (3 6^{\circ}) sin (1 8^{\circ}) = sin (5 4^{\circ}) - sin (1 8^{\circ})

Demostrar que:

2 cos (3 6^{\circ}) sin (1 8^{\circ}) = \frac{1}{2}

Utilizar la identidad trigonométrica del ángulo doble:

sin (2 x) = 2 sin (x) cos (x)

sin (7 2^{\circ}) = 2 sin (3 6^{\circ}) cos (3 6^{\circ})

sin (7 2^{\circ}) sin (3 6^{\circ}) = 4 sin (3 6^{\circ}) sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

Dividir ambos lados entre

sin (3 6^{\circ})

sin (7 2^{\circ}) = 4 sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

Usar la siguiente identidad:

sin (x) = cos (9 0^{\circ} - x)

sin (7 2^{\circ}) = cos (9 0^{\circ} - 7 2^{\circ})

cos (9 0^{\circ} - 7 2^{\circ}) = 4 sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

cos (1 8^{\circ}) = 4 sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

Dividir ambos lados entre

cos (1 8^{\circ})

1 = 4 sin (1 8^{\circ}) cos (3 6^{\circ})

Dividir ambos lados entre

2

\frac{1}{2} = 2 sin (1 8^{\circ}) cos (3 6^{\circ})

Sustituir

\frac{1}{2} = 2 sin (1 8^{\circ}) cos (3 6^{\circ})

\frac{1}{2} = sin (5 4^{\circ}) - sin (1 8^{\circ})

sin (5 4^{\circ}) = cos (9 0^{\circ} - 5 4^{\circ})

\frac{1}{2} = cos (9 0^{\circ} - 5 4^{\circ}) - sin (1 8^{\circ})

\frac{1}{2} = cos (3 6^{\circ}) - sin (1 8^{\circ})

Demostrar que:

cos (3 6^{\circ}) + sin (1 8^{\circ}) = \frac{5}{4}

Utilizar la regla de factorización:

a^{2} - b^{2} = (a + b) (a - b)

a = cos (3 6^{\circ}) + sin (1 8^{\circ})

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} - (cos (3 6^{\circ}) - sin (1 8^{\circ}))^{2} = ((cos (3 6^{\circ}) + sin (1 8^{\circ})) + (cos (3 6^{\circ}) - sin (1 8^{\circ}))) ((cos (3 6^{\circ}) + sin (1 8^{\circ})) - (cos (3 6^{\circ}) - sin (1 8^{\circ})))

Simplificar

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} - (cos (3 6^{\circ}) - sin (1 8^{\circ}))^{2} = 2 (2 cos (3 6^{\circ}) sin (1 8^{\circ}))

Demostrar que:

2 cos (3 6^{\circ}) sin (1 8^{\circ}) = \frac{1}{2}

Utilizar la identidad trigonométrica del ángulo doble:

sin (2 x) = 2 sin (x) cos (x)

sin (7 2^{\circ}) = 2 sin (3 6^{\circ}) cos (3 6^{\circ})

sin (7 2^{\circ}) sin (3 6^{\circ}) = 4 sin (3 6^{\circ}) sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

Dividir ambos lados entre

sin (3 6^{\circ})

sin (7 2^{\circ}) = 4 sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

Usar la siguiente identidad:

sin (x) = cos (9 0^{\circ} - x)

sin (7 2^{\circ}) = cos (9 0^{\circ} - 7 2^{\circ})

cos (9 0^{\circ} - 7 2^{\circ}) = 4 sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

cos (1 8^{\circ}) = 4 sin (1 8^{\circ}) cos (3 6^{\circ}) cos (1 8^{\circ})

Dividir ambos lados entre

cos (1 8^{\circ})

1 = 4 sin (1 8^{\circ}) cos (3 6^{\circ})

Dividir ambos lados entre

2

\frac{1}{2} = 2 sin (1 8^{\circ}) cos (3 6^{\circ})

Sustituir

2 cos (3 6^{\circ}) sin (1 8^{\circ}) = \frac{1}{2}

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} - (cos (3 6^{\circ}) - sin (1 8^{\circ}))^{2} = 1

Sustituir

cos (3 6^{\circ}) - sin (1 8^{\circ}) = \frac{1}{2}

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} - (\frac{1}{2})^{2} = 1

Simplificar

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} - \frac{1}{4} = 1

Sumar

\frac{1}{4}

a ambos lados

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} - \frac{1}{4} + \frac{1}{4} = 1 + \frac{1}{4}

Simplificar

(cos (3 6^{\circ}) + sin (1 8^{\circ}))^{2} = \frac{5}{4}

Obtener la raíz cuadrada de ambos lados

cos (3 6^{\circ}) + sin (1 8^{\circ}) = \pm \frac{5}{4}

cos (3 6^{\circ})

no puede ser negativa

sin (1 8^{\circ})

no puede ser negativa

cos (3 6^{\circ}) + sin (1 8^{\circ}) = \frac{5}{4}

Añadir las siguientes ecuaciones

cos (3 6^{\circ}) + sin (1 8^{\circ}) = \frac{5}{2}

((cos (3 6^{\circ}) + sin (1 8^{\circ})) + (cos (3 6^{\circ}) - sin (1 8^{\circ}))) = (\frac{5}{2} + \frac{1}{2})

Simplificar

cos (3 6^{\circ}) = \frac{5 + 1}{4}

Elevar al cuadrado ambos lados

(cos (3 6^{\circ}))^{2} = (\frac{5 + 1}{4})^{2}

Usar la siguiente identidad:

sin^{2} (x) = 1 - cos^{2} (x)

sin^{2} (3 6^{\circ}) = 1 - cos^{2} (3 6^{\circ})

Sustituir

cos (3 6^{\circ}) = \frac{5 + 1}{4}

sin^{2} (3 6^{\circ}) = 1 - (\frac{5 + 1}{4})^{2}

Simplificar

sin^{2} (3 6^{\circ}) = \frac{5 - 5}{8}

Obtener la raíz cuadrada de ambos lados

sin (3 6^{\circ}) = \pm \frac{5 - 5}{8}

sin (3 6^{\circ})

no puede ser negativa

sin (3 6^{\circ}) = \frac{5 - 5}{8}

Simplificar

sin (3 6^{\circ}) = \frac{\frac{5 - 5}{2}}{2}

= \frac{\frac{5 - 5}{2}}{2}

\frac{\frac{5 - 5}{2}}{2} = \frac{2 5 - 5}{4}

\frac{\frac{5 - 5}{2}}{2}

\frac{5 - 5}{2} = \frac{5 - 5}{2}

\frac{5 - 5}{2}

Aplicar la siguiente propiedad de los radicales:

asumiendo que

a \geq 0, b \geq 0

= \frac{5 - 5}{2}

= \frac{\frac{5 - 5}{2}}{2}

Aplicar las propiedades de las fracciones:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{5 - 5}{2 \cdot 2}

Racionalizar

\frac{5 - 5}{2 2} : \frac{2 5 - 5}{4}

\frac{5 - 5}{2 2}

Multiplicar por el conjugado

\frac{2}{2}

= \frac{5 - 5 2}{2 \cdot 2 2}

2 \cdot 22 = 4

2 \cdot 22

Aplicar las leyes de los exponentes:

a^{b} \cdot a^{c} = a^{b + c}

222 = 2 \cdot 2^{\frac{1}{2}} \cdot 2^{\frac{1}{2}} = 2^{1 + \frac{1}{2} + \frac{1}{2}}

= 2^{1 + \frac{1}{2} + \frac{1}{2}}

Sumar elementos similares:

\frac{1}{2} + \frac{1}{2} = 2 \cdot \frac{1}{2}

= 2^{1 + 2 \cdot \frac{1}{2}}

2 \cdot \frac{1}{2} = 1

2 \cdot \frac{1}{2}

Multiplicar fracciones:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Eliminar los terminos comunes:

2

= 1

= 2^{1 + 1}

Sumar:

1 + 1 = 2

= 2^{2}

2^{2} = 4

= 4

= \frac{2 5 - 5}{4}

= \frac{2 5 - 5}{4}

= \frac{2 5 - 5}{4}

sin (B) = \frac{7 \cdot \frac{2 5 - 5}{4}}{12}

Simplificar

\frac{7 \cdot \frac{2 5 - 5}{4}}{12} : \frac{7 2 5 - 5}{48}

\frac{7 \cdot \frac{2 5 - 5}{4}}{12}

Multiplicar

7 \cdot \frac{2 5 - 5}{4} : \frac{7 5 - 5}{2 2}

7 \cdot \frac{2 5 - 5}{4}

Multiplicar fracciones:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 5 - 5 \cdot 7}{4}

Factorizar

4 : 2^{2}

Factorizar

4 = 2^{2}

= \frac{7 2 5 - 5}{2 ^{2}}

Cancelar

\frac{2 5 - 5 \cdot 7}{2 ^{2}} : \frac{7 5 - 5}{2 ^{\frac{3}{2}}}

\frac{2 5 - 5 \cdot 7}{2 ^{2}}

Aplicar las leyes de los exponentes:

2 = 2^{\frac{1}{2}}

= \frac{7 \cdot 2 ^{\frac{1}{2}} 5 - 5}{2 ^{2}}

Aplicar las leyes de los exponentes:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{2 ^{\frac{1}{2}}}{2 ^{2}} = \frac{1}{2 ^{2 - \frac{1}{2}}}

= \frac{7 5 - 5}{2 ^{2 - \frac{1}{2}}}

Restar:

2 - \frac{1}{2} = \frac{3}{2}

= \frac{7 5 - 5}{2 ^{\frac{3}{2}}}

= \frac{7 5 - 5}{2 ^{\frac{3}{2}}}

2^{\frac{3}{2}} = 22

2^{\frac{3}{2}}

2^{\frac{3}{2}} = 2^{1 + \frac{1}{2}}

= 2^{1 + \frac{1}{2}}

Aplicar las leyes de los exponentes:

x^{a + b} = x^{a} x^{b}

= 2^{1} \cdot 2^{\frac{1}{2}}

Simplificar

= 22

= \frac{7 5 - 5}{2 2}

= \frac{\frac{7 5 - 5}{2 2}}{12}

Aplicar las propiedades de las fracciones:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{7 5 - 5}{2 2 \cdot 12}

Multiplicar los numeros:

2 \cdot 12 = 24

= \frac{7 5 - 5}{24 2}

Racionalizar

\frac{7 5 - 5}{24 2} : \frac{7 2 5 - 5}{48}

\frac{7 5 - 5}{24 2}

Multiplicar por el conjugado

\frac{2}{2}

= \frac{7 5 - 5 2}{24 2 2}

2422 = 48

2422

Aplicar las leyes de los exponentes:

a a = a

22 = 2

= 24 \cdot 2

Multiplicar los numeros:

24 \cdot 2 = 48

= 48

= \frac{7 2 5 - 5}{48}

= \frac{7 2 5 - 5}{48}

sin (B) = \frac{7 2 5 - 5}{48}

Aplicar propiedades trigonométricas inversas

sin (B) = \frac{7 2 5 - 5}{48}

Soluciones generales para

sin (B) = \frac{7 2 5 - 5}{48}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

B = arcsin (\frac{7 2 5 - 5}{48}) + 36 0^{\circ} n, B = 18 0^{\circ} - arcsin (\frac{7 2 5 - 5}{48}) + 36 0^{\circ} n

B = arcsin (\frac{7 2 5 - 5}{48}) + 36 0^{\circ} n, B = 18 0^{\circ} - arcsin (\frac{7 2 5 - 5}{48}) + 36 0^{\circ} n

Mostrar soluciones en forma decimal

B = 0.34997 \dots + 36 0^{\circ} n, B = 18 0^{\circ} - 0.34997 \dots + 36 0^{\circ} n

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