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人気のある三角関数 >

2cos(x)+3cos(x)-2=0

解

2 cos (x) + 3 cos (x) - 2 = 0

解

x = 1.15927 \dots + 2 πn, x = 2 π - 1.15927 \dots + 2 πn

+1

度

x = 66.42182 \dots^{\circ} + 36 0^{\circ} n, x = 293.57817 \dots^{\circ} + 36 0^{\circ} n

解答ステップ

2 cos (x) + 3 cos (x) - 2 = 0

簡素化

2 cos (x) + 3 cos (x) - 2 : 5 cos (x) - 2

2 cos (x) + 3 cos (x) - 2

類似した元を足す:

2 cos (x) + 3 cos (x) = 5 cos (x)

= 5 cos (x) - 2

5 cos (x) - 2 = 0

2

を右側に移動します

5 cos (x) - 2 = 0

両辺に

2

を足す

5 cos (x) - 2 + 2 = 0 + 2

簡素化

5 cos (x) = 2

5 cos (x) = 2

以下で両辺を割る

5

5 cos (x) = 2

以下で両辺を割る

5

\frac{5 cos ( x )}{5} = \frac{2}{5}

簡素化

cos (x) = \frac{2}{5}

cos (x) = \frac{2}{5}

三角関数の逆数プロパティを適用する

cos (x) = \frac{2}{5}

以下の一般解

cos (x) = \frac{2}{5}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{2}{5}) + 2 πn, x = 2 π - arccos (\frac{2}{5}) + 2 πn

x = arccos (\frac{2}{5}) + 2 πn, x = 2 π - arccos (\frac{2}{5}) + 2 πn

10進法形式で解を証明する

x = 1.15927 \dots + 2 πn, x = 2 π - 1.15927 \dots + 2 πn

グラフ

人気の例

sec((5θ)/4)=2,[0.2pi]

sec (\frac{5 θ}{4}) = 2, [0.2 π]

cos(x)+|cos(x)|=1,-2pi<= x<= 2pi

cos (x) + ∣ cos (x) ∣ = 1, - 2 π \leq x \leq 2 π

(30.56)/(sin(88))=(17)/(sin(x))

\frac{30.56}{sin ( 8 8 ^{\circ} )} = \frac{17}{sin ( x )}

sec(x+pi/4)=-sqrt(2),-pi<= x<= pi

sec (x + \frac{π}{4}) = - 2, - π \leq x \leq π

(56)/((7.071*7.681))=cos(θ)

\frac{56}{( 7.071 \cdot 7.681 )} = cos (θ)